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This value is 0,2 g hydrogen.

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9y ago
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9y ago

The equation 2 H2 + O2 --> 2 H2O indicates that for every mole of water produced, 1 mole of hydrogen is needed. 1.8 grams of water is .0999 moles, and .0999 moles of hydrogen is .201 grams.

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11y ago

Each water molecule contains exactly 2 hydrogen atoms and one oxygen atom. The gram Atomic Mass of oxygen is 15.9994, and the gram atomic mass of hydrogen is 1.008. Therefore, the ratio by mass of water to the oxygen contained in the water is [(2)(1.008) + 15.9994]/15.9994 or about 1.126. 20 grams of oxygen will form 22.52 grams of water,of which2.5 grams, to the justified number of significant digits,will be hydrogen.

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7y ago

The ratio of atomic weights for hydrogen and oxygen is 1/16 so the ratio in a water molecule which has 2 hydrogens for each oxygen would be 2/16. Another way to look at it is that the ratio of the mass of hydrogen in a water molecule to the total mass of the molecule would be 2/18. For 1.8 g of water this is equivalent to 0.2/1.8, i.e. you need 0.2 g of hydrogen to produce 1.8 grams of water.

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9y ago

Consider the chemical equation 2H2 + O2 -> 2H2OThe molecular mass of H2O is 18.0
Amount of water to be produced = 1.80/18.0 = 0.100mol

By the stoichiometry of the chemical reaction, 2 moles of hydrogen with 1 mole of oxygen will produce two moles of water.

So, 0.100mol of hydrogen would be needed.

Mass of hydrogen needed = 2.0 x 0.100 = 0.200g

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6y ago

Reaction of H2 with N2 is as follows:3H2 + N2 ==> 2NH3 balanced equation

2.80 g N2 x 1 mole N2/28 g = 0.1 moles N2 present

0.1 moles N2 x 3 moles H2/1 moles N2 = 0.3 moles H2 needed

0.3 moles H2 x 2 g/mole = 0.6 g of H2 needed

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11y ago

1.78g as oxygen accounts for 89% of the mass of pure water.

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9y ago

There are 0.1 moles of water in 1.80g of water. So 0.1 moles of hydrogen is needed to produce 1.80g of water. Molecular mass of H2 is 2g/mol. Therefor 0.2g of H2 is needed.

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9y ago

This value is 0,2 g hydrogen.

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12y ago

0.89

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