How many joules of heat are necessary to raise the temperature of 25 g of water from 10 degrees Celsius to 60 degrees Celsius?

Answer 1

For an approximate calculation:

specific heat capacity for water = 4.18 J/(g*degC)

(how much energy is required per gram per change in degrees C)

mass = 25g

Change in temperature = 60-10 = 50 degC

energy required = mass * change in temperature * specific heat capacity

= 25g * 50 degC * 4.18 J/(g*degC)

Answer 2

Specific Heat capacity( S) is the amount of heat required to raise the temperature of unit mass of substance through 10C.

Let H be heat supplied, T be temperature change, m be mass of body.

Now as per our definition

Specific Heat capacity = heat supplied/mass of body*temperature change

or S = H/T*m

Putting values into the formula we have:

S = 26kJ/250g*1670C

S = 26000J/(1/4 kg * 1670C)

S = 622.75 J/kg* 0C

Hence Specific Heat capacity of substance = 622.75 J/kg* 0C.

This is done by assuming no phase change occurs during heating and substance remained in the same state as on beginning.

Answer 3

Using the equation Q=MC theta 600J= 0.25*C*3 600J= 0.75*C 600J/.75=C 600J*1/4=C C=15J/Kg centigrade

Answer 4

2.22 J/g°C