100.... The size of a unit of heat energy in the Celsius and Kelvin temperature system is the same. Thus the difference between the boiling and freezing points of water at standard pressure is 100 units on either scale.
100 (same as Celsius)
I think it's 273K
100 kelvins
273
373.15 K (Note that the degree sign is not used with the Kelvin scale)
273.15 kelvin because 1 ATM is reffering to the normal atmospheric pressure so it is the normal freezing point converted to kelvin Rob
273 degrees kelvin
Standard temperature is defined as zero degrees Celsius (0 0C), which translates to 32 degrees Fahrenheit (32 0F) or 273.15 degrees kelvin (273.15 0K). This is essentially the freezing point of pure water at sea level, in air at standard pressure.
273.15K is the melting point of water in kelvin That's not correct; water boils at 100 degrees Celsius, to go from C to K, you add 273 to the Celsius temperature... 100+273 = 373 degrees K
Kelvin = Celsius + 273.15 therefore (assuming you are referring to the freezing point of water, 0C) freezing point = 273.15K
273.15 Kelvin.
373.15 K (Note that the degree sign is not used with the Kelvin scale)
373.15 K at standard pressure
At standard pressure the melting (freezing) point of pure water is 0 0C.
The freezing point of water is zero degrees Celsius at standard pressure.
Around 1800 Kelvin.
Dear Wiki Questioner, The freezing point of water occurs at 273.15 K. We can calculate this because water freezes at 0 degrees Celsius, and we can convert from Celsius to Kelvin with the following Formula: Temperature in Kelvin = 273.15 + Temperature in Celsius So if our Temperature of freezing water in Celsius is 0 degrees, we know that our temperature in Kelvin is 273.15 + 0 = 273.15
273.15 kelvin because 1 ATM is reffering to the normal atmospheric pressure so it is the normal freezing point converted to kelvin Rob
kelvin
Freezing point: 273.15 K Melting point: 373 K
Freezing point: 273.15 K Melting point: 373 K