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How many liters of 4 M solution can be made using 100 grams of lithium bromide?
Wiki User
∙ 13y ago
M=#mol solute / Liter of solution
#mol solute= mass / molar mass
#mol solute= 100 / 87 = 1.15
4= 1.15 / L solution
1.15 / 4 = 0.28
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Since we were only given the (M) and grams of LiBr we had to find the mol of solute. To find the #mol of solute we divided the grams (which were given) over the molar mass of LiBr (87). We then got 1.15 . Now we are able to find the Liter of solution . First we plugged in our given values M= 4 & #mol solute= 1.15 . To find liter of solution we simply dived 1.15 over 4 which equals 0.28.
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I suppose that lithium bromide is not so soluble to prepare 4 M solutions in water at 20 0C.
Wiki User
∙ 13y ago
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