How many mL of the 0.5 M NaCl stock solution is needed to prepare 500mL of 0.25 M NaCl solution How much water is needed to dilute the stock solution?

(ml NaCl )(1M NaCl) = (200ml NaCl )(0.05M NaCl ) = 10 ml

You have to evaporate (by open boiling) 45 mL of the 75 mL 2M NaCl solution thus reducing the volume to 30 mL 5M NaCl.

One mole of NACl (also known as table salt) is 58.5 gram so you need 0.0585 gram of NaCl in one litter.

1000 ppm = 1000 mg/ l 1N NaCl = 58.5 gm/l ok 1000 mg/l = 1 gm/l = 0.1gm/100 ml = 0.1 % wt. on the other hand 1 % wt. = 10,000 ppm so , 0.1 %wt. = 1000 ppm so you...

Let us find moles first. Molarity = moles of solute/Liters of solution ( 750 ml = 0.75 o Liters ) 0.375 M Na2SO4 = moles Na2SO4/0.750 Liters = 0.28125 moles Na2SO4 . 0.28125 moles Na2SO4 (142.05...