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P=rho*g*h

P= pressure

rho= density = 1000 kg/m^3 at about 20C

g= gravitational constant on earth at sea level = 9.81 m/s^2

h= height

P=1 bar=1x10^5 Pascals = 1x10^5 N/m^2 (based on the definition of the Pascal unit)

since by definition 1 Newton= 1 kg*m/s^2

1x10^5 N/m^2= 1x10^5 kg*m^2/(m^3*s)= 1x10^5 kg/(m^2*s)

1x10^5 kg/(m^2*s) = 1000 kg/m^3 *9.81m/s^2 * h

solving for h yields:

h= 1x10^5/(1000*9.81)= 10.19367 meters

This value might vary slightly due to the affect of temperature on the density of water.

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13y ago
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15y ago

Depends on the altitude. But its meters of head times 0.09804 for calculating bar. Thus 1 meter of head, times 0.09804 tells us a meter of head is 0.09804 bar of pressure

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14y ago

1 BAR = 10 Meters

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Q: How many meters of water is 1 bar?
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