How many moles of argon are present in 100.0 grams of argon?

Have: 607gAr Need: Moles of ArgonFrom the periodic table we know that there are 39.948gAr per every 1 mole of Argon.607g/39.948 = your answer.

Argon has an atomic mass of 39.948. Therefore, it has 39.948 grams per mol.Ar(mol) = 14.5 g / 39.948 g/molAr(mol) = 0.363 mol

For this you need the atomic (molecular) mass of CS2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. CS2=76.2 grams 10.00 moles CS2 × (76.2...

For this you need the atomic (molecular) mass of H2O. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. H2O=18.0 grams 100.0 grams H2O / (18.0...

1 mole Ar = 39.948g Ar (atomic weight in grams) 2.6g Ar x (1mol Ar/39.948g Ar) = 0.065mol Ar