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How many moles of argon in 607 g of argon?

Answer:

Have: 607gAr Need: Moles of Argon
From the periodic table we know that there are 39.948gAr per every 1 mole of Argon.

607g/39.948 = your answer.

First answer by ID1613050136. Last edit by ID1613050136. Question popularity: 1 [recommend question].

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What is the number of moles of argon in 607 g of argon?
the equation isXg multiplied by the moles/grams of X = moles of X(the grams cancel leaving you with moles)607g Ar x 1 mole/ 39.95g = 15.19 moles
How many moles of argon are in 14.5 g of argon?
Argon has an atomic mass of 39.948. Therefore, it has 39.948 grams per mol.Ar(mol) = 14.5 g / 39.948 g/molAr(mol) = 0.363 mol
Number of argon moles in 119.98 g of argon?
The mass number of Argon is 39.948 so it is 119.98/39.948=3.0034 moles of Argon in 119.98 g of Argon or approximately 3 moles of Argon is in 119.98 g this gas.
How many moles are in 22grams of argon?
From the Periodic Table, Argon has an atomic weight of 39.948. One mole of any element is equal to its atomic weight in grams. So 1 mole of Ar = 39.948g of Ar. Using that equality, you do the...
How many moles in 2.6 grams of Argon?
1 mole Ar = 39.948g Ar (atomic weight in grams) 2.6g Ar x (1mol Ar/39.948g Ar) = 0.065mol Ar