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3.982 g C6H4Cl2 (1 mole C6H4Cl2/146.992 grams)(6 mole C/1 mole C6H4Cl2)(6.022 X 10^23/1 mole C)(1 mole C/6.022 X 10^23)

= 0.1625 moles of Carbon atoms

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13y ago
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Q: How many moles of carbon atoms in dichlorbenzene 3.982 g C6H4Cl2?
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