How many ways can you arrange the letters A B C D E and F in a row?

Answer 1

First, count how many letters you have--A, B, C, D, E, and F--6.

Then, the problem is the number multiplied by the ones below it. 6x5x4x3x2x1.

You can get rid of the one, because anything multiplied by 1 is itself.

6x5x4x3x2=720.

You can arrange these six letters in 720 possible ways.

If the row could be vertical or horizontal, the number doubles to 1440.

Answer 2

se foramula is

(length of string)!/(product of factorial of length of all repeated string)

e.g

abcdef = 6!/0!

abbcdef = 7!/2!

Answer 3

24 ways