A microprocessor that uses 24 bit addressing, such as the Intel 80286, can address 224 or 16,777,216 memory locations. The IBM MainFrame, 360/44 or any modern version running in AMODE=24 also has the same capacity.
Each address line can be either a 1 or a 0 since microprocessors are binary based. This means that the total number of combinations is 2 ^ 14 or 4096 different addresses. The address range would then be 0 to 4095.
The maximum addressable memory for a computer with a 24 bit address bus is 16 Mb. This value has nothing to do with the size of the instruction format.
A computer with a 12 bit address bus can directly address 2^12 locations, or 4096 locations.
address space = 24 bits-->(2 power 24)=16 M words
320 kilobytes
2^14 memory locations. In general for n-bit address bus, its 2^n
2^14 memory locations. In general for n-bit address bus, its 2^n
The 8085 can address 216, or 65536 different memory locations.
16KB
A 14 bit address bus can select 16384 locations.
A 16 bit address bus can select 65536 locations.
Different microprocessor can address different amounts of memory. The motherboard design should allow for maximising the physical memory to what the microprocessor can address
You can address 214 or 16384 different locations with 14 address lines.
There is no microprocessor with !t of address memory, only virtual memory. the firt one was the 80486.
A microprocessor with 12 address lines is capable of addressing 4096 locations in memory. The Intel 4004 and the DEC PDP-8 are examples of processors with 12 address lines.
The 8086/8088 microprocessor has a 20 bit address bus, so the number of memory locations it can address is 220 or 1,048,576.
32 bit address line can access 4GB of memory. As 2^10 -> 1KB; 2^20 -> 2MB; 2^30 -> 1GB and so on.... 32 bit gives (2^30) * (2^2) = 1GB * 4 = 4GB;