How much current flows through a standard 100 watt floodlight when operated at its designed voltage of 120V?

Power[Watt] = Voltage[Volts] x Current[Amperes], i.e. P = VI -----[1] In current situation: Power = 100 Watt Voltage = 120 Volts Thus, Current I = P/V, from eqn.[1] => I = 100/120 =>...

According to Ohm's law(V=IR) . I think 0.25 Ampere.

V = IR = 8x10-3 (8 mA) * 10x103 (10k) = 80v

5 Amps.

http://en.wikipedia.org/wiki/Incandescent_light_bulb lists the resistance for a cold lightbulb at ~9.5ohm. I = V/R , or 120/9.5 = 12.6 amps. After ~13ms the bulb is at peak resistance (~144ohm) and...