Here is the formula, Per hour consumption = Diesel consumed / Total DG run hours Diesel consumed = Previous closing balance - Actual closing balace Daily DG run hours = (Total DG run hours / (DG capacity*24 - Total DG run hours)) * 24 / (( Total DG run hours / ( DG capacity * 24 - Total DG run hours )) + 1 Regards, Shibin shibin.hesel@gmail.com
It's because the voltage is a specified value, and the current drawn has a limiting value. So multiplying those together gives the VA or kVA that it can supply.
DG set is designed for 0.8 lag power factor. if it fall below this, we can used proper rating capacitor to improve this. what happens if we run the DG at .6 pf
In theory, you should be able to load your generator to 15 kV.A (mine stalls far below that load, though!!!). So, divide this figure by the rated output voltage of the generator, and this tells you the maximum current it can supply. The sum of your individual loads should not exceed that value of current. (The current drawn by an individual load is its power rating divided by the supply voltage -just add them up!).
covernor
It is 7 .5 litre per hour
Here is the formula, Per hour consumption = Diesel consumed / Total DG run hours Diesel consumed = Previous closing balance - Actual closing balace Daily DG run hours = (Total DG run hours / (DG capacity*24 - Total DG run hours)) * 24 / (( Total DG run hours / ( DG capacity * 24 - Total DG run hours )) + 1 Regards, Shibin shibin.hesel@gmail.com
Rating for DG set and any of electrical machines is calculated in KVA. KVA is calculated as KW/pf. One can calculate the required KVA for DG set with this formulation: (KW/pf)/load rate. For example KW=110, pf=0.8 and one loads the DG at 75%, so KVA= (110/0.8)/0.75=185 KVA.
What is the minimum height required for chimney of 100 KVA DG Set which is kept in
what should be height of stack of 1250 kva D.G as per Indian pollution boardA: it should be 7.1 meter + building height of 1250kva Dg set installed.
I=Kva*1000/v*1.732 =500*1000/415*1.732 =500,000/718.78 =695.62 Amps. So max.load of 500kva DG is 695.62 Amps
On an average load on a 15 kc DG is about 4 littered of diesel per hour.
Diesel Generator
max.load that can run on 62 kva dg is of 86 amperes.
It's because the voltage is a specified value, and the current drawn has a limiting value. So multiplying those together gives the VA or kVA that it can supply.
If your DG engine oil consuming more means : - You are running DG without loador lower than 30% of the DG Capacity.
1- low lube oil safety 2-water safety 3-temprechar safety any athar safety