For M20 grade concrete mix proportion=1:1.5:3
And dry volume factor is 54 percent.
Hence, we required to find quantities for 1.54 cum concrete.
cement required=(1/5.5) x (1.54)=0.27 cum,
Sand required=(1.5/5.5) x (1.54)=4.2 cum,
Stone chips required=(3/5.5) x (1.54)=0.84 cum.
Type your answer here... 11.2
M20 - 6.20bags
One cubic metre of concrete weighs 2.5 Tonnes. Typically, 1m3 of concrete is made up of 350Kg of cement, 700Kg of sand, 1,200Kg of chippings and 150 Litres of water.
1:2:4 i.e. i cement, 2 sand and 4 aggregate...
It depends on the required grade of concrete, you need to know the particular grade. The three grades specify the ratios of Cement : Stone : Sand. M15 = M150 = 1 : 2 : 4 M20 = M200 = 1 : 1.5 : 3 M25 = M250 = 1 : 1 : 2 As you can see there is always two parts sand to one part stone. Higher grades have more cement. So the ratio of stone to the whole is 2:7, 3:11, and 1:4. The percentages are 28.6%, 27.3%, and 25.0%.
Type your answer here... 11.2
315 Kg/M3 approx.
M20 - 6.20bags
M 15 grade proportion - 1:2:4 (cement:FA:CA)Cement required in kgs - 325 kg per cu.mNo. of bags required - 6.50
M 25 grade proportion - 1:1:2Cement in kgs - 479 per cu.mNo.of bags required - 9.58 bags.
One cubic metre of concrete weighs 2.5 Tonnes. Typically, 1m3 of concrete is made up of 350Kg of cement, 700Kg of sand, 1,200Kg of chippings and 150 Litres of water.
it should depend in which construction you going to be used the concrete....means it is used in a house or in a big project like a massive dam...........like the ratio of "C:S:A "C= CEMENT S= SAND(FINE AGREEGATE) A=AGREEGATE (COARSE AGG)IN SOME TIME IT USED AS THE RATIO OF 1:2:4OR 1:1.5:3 AND RATIO IS USED TO FIND THE QUANTITY OF SAD AND AGREEGATE...............1 cubic feet of concrete requires how much coarse aggregate and fine aggregate?ANSWER :Grade is M20 and ratio for M 20 is 1:1.5:3void ratio for cement is 100 % compressivevoid ratio for fine aggregate 20 %void ratio for coarse aggregate 32% , from IS codeNOTE : (that means cement have compressive in 100%fine Aggregate needs compressive in 20 %coarse Aggregate needs compressive 10 32 % , from IS code )total ratio for mix is 1.52cement = 1fine aggregate = 1.5coarse aggregate = 3total is 1 + 1.5 + 3 = 5.5take now all dimension meter only , convert it in feet with end of the solutionCEMENT = [(1 X 1 X 1.52 X) / 5.5 ]= 0.28 m³1 is required quantityAnother 1 is cement ratio1.52 is total compressive for concreteTotal ratio is 5.550 Kg per bag of cement is 0.0347 m³No of bags required for 1 m³ of concrete is.28 m³ / .0347 m³ = 8.07 bags take 8 bagsCEMENT = 9.88 cubic feetFINE AGGREGATE = [ ( 1 X 1.5 X 1.52 ) / 5.5 ) = 0.41 m³Here 1.5 is fine aggregate ratio , remaining is same as above.1 m³ = 35.29 cubic feet1 cubic feet = .03 m³F.AGG = 14.47 cubic feetCOARSE AGGREGATE = [ ( 1 X 3 X 1.52 ) / 5.5 ) = 0.83 m³Here 3 is ratio of coarse aggregateC. AGGREGATE = 29.29 cubic feetANS :CEMENT = 9.88 cubic feetF.AGG = 14.47 cubic feetC. AGGREGATE = 29.29 cubic feetNote : [ 100 cubic feet is 1 brass1 m³ = 35.29 f³1 f3 = 1 m³ / 35.29 = 0.03 m³
For M20 grade concrete, the mix proportion is 1:1.5:3 (cement:sand:coarse aggregates). If we consider a volume of 1 cubic meter, approximately 320 kg of cement would be needed.
15 milligrams
M 15 grade - 1:2:4Cement bags required - 6.5 bagsCement required - 325 kgs
1:2:4 i.e. i cement, 2 sand and 4 aggregate...
For M10 (1:3:6) Grade of concrete cement bag consumed = 4.4 bags/cum M15(1:2:4) Grade of concrete cement bag consumed = 6.6 bag/cum M20(1:1.5:3) Grade of concrete cement bag consumed = 8.2 bag/cum