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pH = -log10[H+], where [H+] is the hydrogen ion concentration.

So, in this case, pH = -log10[1], yielding pH = 0.

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Q: How to calculate pH of 1N HCl solution?
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Which is better to adjust pH 1N HCl or conc HCl?

1N - conc will change the pH too quickly. You might want to consider 0.1molar for finer adjustments.


The pH of a 0.01 M solution of HCl in water would be?

pH = - log[H+] so a 0.01 M solution of HCl has, pH= 2


How calculate pH for a solution?

HCl is a strong acid and dissociates completely. Therefore it can be found using the equation: ph= -log [H+]


What is the pH of a 0.001 M of HCl solution?

its PH is 3


What is the pH of a solution of 0.010 M HCl?

Its pH value is 2.


What is the pH of a 1.0x10-4m hcl solution?

- log(0.00450 M HCl)= 2.3 pH=======


The pH in aqueous solution of hcl at 25c is 4 hcl0.003 moles was added to 1l of this solution calculate the new pH in the solution assume complete dissociation of hcl?

if its complete dissociation, then the products would be a salt and water, which means the pH is 7 or neutral. OMG, if the pH is currently 4 then [H+] = 1.0 e-4 M (pH = -log[H+]) if you add 0.003 moles then 1.0e-4 M +.003 M = .0031 M (Since the strong acid HCL completely dissociates in aq solution) pH = -log [.0031M] = 2.51


What is the pH of 10.0L of 0.0020 M HCL?

0.002M HCl means 0.002 moles HCl in 1L solution. Therefore 0.02 moles HCl in 10L solution. pH = 2-log2 = 2-0.3010 = 1.6990


How many moles of HCL is present in 1 liter of stomach solution that has a PH of 1?

In solution with a pH of 1 [H+] is 0.1M. Since HCl is a strong acid [HCl] will also be 0.1M. So, in 1 liter of solution you will have 0.1 mol of HCl.


What is pH value of 1N HCl?

In 0.01 M of HCl, the concentration of the Hydronium ions is 0.01M as well since HCl is monoprotic. pH = -log [H3O+] = -log 0.01 = -log10-2 = -(-2log10) = 2 Thus, the pH of 0.01 M HCl is 2.


Calculate the pH of 0.01m hcl?

HCl is a strong acid, so we assume that it completely breaks up into ions in solution. HCl ----> H+ & Cl- if we have 0.01m of HCl, it will give 0.01m of H+ and 0.01m Cl- pH = -log [H+] pH = -log 0.01 pH = 2


What is the pH of a 0.280 molar HCl solution?

pH = -log(0.280) = 0.553