Eat better and walk around your neighborhood. I am overweight and I have been watching what I eat and I lost 23 pounds.
to eat many food,like a pig
0.5 kg m/s by the law of conservation of momentum
69 m/s
69 m/s
I don't think there is any equivalency.... A watt isW = J/s = (N*m)/s = ((kg*(m/s^2))*m)/s = kg*(m^2))/(s^3)Therefore: W*kg = (kg^2)*((m^2)/(s^3)) which is not equal to N = kg*(m/s^2)I guess the closest answer would be :1 kg*W = (1 kg*m/s) N or1 kg*W = (1 N*s) N
Let's see. KE = 1/2mV^2 Bullet: KE = 1/2(0.0020 kg)(400 m/s)^2 = 160 Joules ------------------------------- Ocean Liner: KE = 1/2(6.4 X 10^7 kg)(10 m/s)^2 = 3.2 X 10^9 Joules ----------------------------- The linear by a long shot!
0.4 kg(3 m/s) + 0.8kg(-2 m/s) = 1.2 kg m/s -1.6 kg m/s = -0.4 kg m/s -0.4 kg m/s = 1.2 kg(v) = (-0.4 kg m/s)/(1.2 kg) = v = -0.33 m/s the cars are traveling at 0.33 m/s in the direction of the second car.
60 kg-m/s Just took the test
36
(4 kg)*(2 m/s) = 8 kg•m/s
The momentum of a 1400 kg car traveling at 25 m/s is: momentum = mass x velocity momentum = 1400 kg x 25 m/s momentum = 35,000 kg m/s Therefore, the momentum of the 1400 kg car traveling at 25 m/s is 35,000 kg m/s
12,000 kg-m/s
F=ma F=7kg*9.81m/s**2 F=68.67N