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How would Le Chatelier's principle a change in pressure affect a gaseous system in equilibrium?
Wiki User
∙ 6y ago
Verified answer
The equalibrium would shift to reduce the pressure
big man
Wiki User
∙ 6y agoThe system is self-readjusted to equilibrium by a change in another parameter.
How would a change in pressure affect a gaseous system in equilibrium, according to Le Chatelier's principle?
The answer is "The equilibrium would shift to reduce the pressure change" on Apex
According to le chatelier principle how would a change in pressure affect a gaseous system in equilibrium?
The answer is "The equilibrium would shift to reduce the pressure change" on Apex
How would a drop in pressure affect a gaseous system at equilibrium?
the reaction would shift to favor the side with the most moles of gas. (apex).
What factors affect the vapour pressure of a liquid?
Vapor pressure or equilibrium vapor pressure are the pressure of a vapor in thermodynamic equilibrium with its condensed phases in a closed bottle. All liquids and solids have a tendency to evaporate into a gaseous form, and all gases have a tendency to condense back to their liquid or solid form.The equilibrium vapour pressure is an indication of a liquid's evaporation rate. It relates to the tendency of particles to escape from the liquid (or a solid). A substance with a high vapour pressure at normal temperatures is often referred to as volatile
What does Le Châteliers principle state?
Le Chatelier's principle essentially states that if a stress is imposed on a system at equilibrium, the equilibrium will shift to minimize the stress. These stresses include: -Change in temperature -Change in pressure/volume (for gases) -Change in concentration A simple example of this: N2(g) + 3 H2(g) ⇌ 2 NH3(g) ΔH = −92kJ/mol -If you add N2(g) or 3 H2(g) the equilibrium will shift to the right (to the products), and more NH3(g) will be created so as to minimize the stress. - If you add NH3(g), the equilibrium will shift to the left (to the reactants), and more N2(g) and H2(g) will be created. -If you increase the temperature, the equilibrium will shift to the left (to the reactants). The reason for this is that the above reaction is exothermic, and releases heat. Consequently, the heat is on the side of the products, and thus if you add heat, the equilibrium will shift to the reactants and more N2(g) and H2(g) will be created. - If you increased the pressure, which is the same as decreasing the volume, the reaction will shift to the side with fewer moles, which, in this case, is the products. Thus, more NH3(g) will be created. -Conversely, if you decrease the pressure (increase the volume), the reaction will shift to the side with a greater number of moles, which, in this case, is the reactants. Thus, more N2(g) and H2(g) will be created. *It is important to note that changing pressure and volume only effects the equilibrium in gaseous reactions!
According to le chatelier principle how would a change in pressure affect a gaseous system in equilibrium?
The answer is "The equilibrium would shift to reduce the pressure change" on Apex
How would a change in pressure affect a gaseous system in equilibrium, according to Le Chatelier's principle?
The answer is "The equilibrium would shift to reduce the pressure change" on Apex
according to le chatelier's principle, how would a change in pressure affect a gaseous system in equilibrium?
The answer is "The equilibrium would shift to reduce the pressure change" on Apex
How would a drop in pressure affect a gaseous system equilibrium?
the reaction would shift to favor the side with the most moles of gas. (apex).
Would a drop in pressure affect a gaseous system at equilibrium?
the reaction would shift to favor the side with the most moles of gas. (apex).
How would a drop pressure affect a gaseous system at equilibrium?
the reaction would shift to favor the side with the most moles of gas. (apex).
How would a drop in pressure affect a gaseous system at equilibrium?
the reaction would shift to favor the side with the most moles of gas. (apex).
How according to le châtelier's principle how will a pressure increase affect a gaseous system?
The total number of gas molecules will decrease.
Does addition of noble gas effect partial pressures in gaseous equilibrium system?
Yes. If the pressure is increased, even with a noble gas, the reaction equilibrium will shift to alleviate and lower that increased pressure (if there are more moles of gas on one side of the reaction than the other).
What factors affect the vapour pressure of a liquid?
Vapor pressure or equilibrium vapor pressure are the pressure of a vapor in thermodynamic equilibrium with its condensed phases in a closed bottle. All liquids and solids have a tendency to evaporate into a gaseous form, and all gases have a tendency to condense back to their liquid or solid form.The equilibrium vapour pressure is an indication of a liquid's evaporation rate. It relates to the tendency of particles to escape from the liquid (or a solid). A substance with a high vapour pressure at normal temperatures is often referred to as volatile
What does Le Châteliers principle state?
Le Chatelier's principle essentially states that if a stress is imposed on a system at equilibrium, the equilibrium will shift to minimize the stress. These stresses include: -Change in temperature -Change in pressure/volume (for gases) -Change in concentration A simple example of this: N2(g) + 3 H2(g) ⇌ 2 NH3(g) ΔH = −92kJ/mol -If you add N2(g) or 3 H2(g) the equilibrium will shift to the right (to the products), and more NH3(g) will be created so as to minimize the stress. - If you add NH3(g), the equilibrium will shift to the left (to the reactants), and more N2(g) and H2(g) will be created. -If you increase the temperature, the equilibrium will shift to the left (to the reactants). The reason for this is that the above reaction is exothermic, and releases heat. Consequently, the heat is on the side of the products, and thus if you add heat, the equilibrium will shift to the reactants and more N2(g) and H2(g) will be created. - If you increased the pressure, which is the same as decreasing the volume, the reaction will shift to the side with fewer moles, which, in this case, is the products. Thus, more NH3(g) will be created. -Conversely, if you decrease the pressure (increase the volume), the reaction will shift to the side with a greater number of moles, which, in this case, is the reactants. Thus, more N2(g) and H2(g) will be created. *It is important to note that changing pressure and volume only effects the equilibrium in gaseous reactions!
Temperature where some of a liquid begins to enter the gaseous state?
All substances can have a gaseous state, however, below the triple point (the temperature and pressure at which solid, liquid and gas can co-exist in equilibrium), the equilibrium is between the solid state and the gaseous state. Once you get above the triple point, you can get a gaseous state as long as you are above the melting point of the substance and below the critical point (the temperature at which the gas and liquid states have the same density - above the critical point you get a single "supercritical" phase). Between the triple point pressure and the critical point pressure, the temperature at which some liquids begin to get a gaseous state is know as the "boiling point". For water at sea level, that happens around 100 °C (212 °F) - although anyone who has been camping at high altitudes can attest to the fact that with the lower pressure at high altitudes, the boiling point of water can drop to something barely luke warm.
