Answer:
The cube is a special case of the cuboid (where length = breadth = height), so we will only consider the total surface area of a cuboid.
Let the cuboid have length l, breadth b and height h.
Then the surface area of the cuboid consists of 2 l x b rectangles, 2 b x h rectangles, and 2 l x h rectangles.
As such, the total surface area is 2bl + 2bh + 2lh = 2(bl + bh + lh).