How do you figure out slopes?

Answer 1

the forula of slope is :

* Y2- Y / X2 - X

* the x2 , y2 means the second varible

example:

(4, 10) (-5, 7)

* 4= X 10=Y -5=X2 7=Y2

7-10 / -5 -4= 1/3

* y= mx + b

1/3x + b

1/3(-5) +b

-5/3 +b

26/3 = b or 8.6666..

*now plug in for forlmula

y= 1/3x + 8.6666... or y=1/3x + 26/3

Answer 2

Remember the phrase "Raise over run".

Take any two points on the line, the left point being the "first point" and the right point being the "second point". Take the difference of the y values (second minus first) and divide that by the difference of the x-values (second minus first). So you get (y2-y1)/(x2-x1)

This method only works on straight lines, to find the slope at points on a curve, you'll will have to learn calculus. If that is what you were asking, let me know an I'll edit this appropriately.

Answer 3

The rise over the run. You look at the change in the y values and divide by the change in the x values Here is an example, say one point is (1,1) and the other is (3,5). The change in the y values is 5-1=4 and the change in the x values is 3-1=2 so the slope is 4/2 or 2. We need to always subtract the the same x as we do the y. So we found the change in y as 5-1 WE CAN'T USE 1-3 for the change in x, we MUST use 3-1 since that is the way we did it for the y. Here is one more for you. point one is (x1,y1) point two is (x2,y2) the slope is (y2-y1)/(x2-x1) we often use the letter m for slope so m=(y2-y1)/(x2-x1) m also equals (y1-y2)/(x1-x2)

Answer 4

You can find the slope (I assume an [x,y] plane) of a line simply by taking the change in y and putting it over the change in x, denoting:

Initial point: (x1,y1)

Final Point: (x2,y2)

Slope: (y2-y1)/(x2-x1)