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The formula for this question is c1v1= c2v2 c1v1= 20ml x 0.01m = 0.02 x 0.01 c2v2= 0.03c2 therefore it is (0.02 x 0.01) / 0.03 = c2 c2 is the molarity of our na-oh solution cheers :D The formula for this question is c1v1= c2v2 c1v1= 20ml x 0.01m = 0.02 x 0.01 c2v2= 0.03c2 therefore it is (0.02 x 0.01) / 0.03 = c2 c2 is the molarity of our na-oh solution.
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∙ 9y ago
Wiki User
∙ 14y agoOne mole of any acid neutralizes one mole of any base.
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How many ml of 250 M NaOH are required to neutralize 30.4 ml of 152 M HCl?
M1V1=M2V2... By plugging in, you get 18.48 mL of NaOH
How many moles of sodium hydroxide are required to neutralize 20 mol of nitric acid?
20 moles of NaOH needed to neutralize 20 moles of nitric acid
How many milliliters of 0.400 M NaOH are required to completely neutralize 20.00 mL of 0.200 M HCl?
10 mL
How many NaOH required to neutralize complitly4.9 gms of H2SO4?
Grams NaOH?? Balanced equation. 2NaOH + H2SO4 --> Na2SO4 + 2H2O 4.9 grams H2SO4 (1 mole H2SO4/98.086 grams)(2 mole NaOH/1 mole H2SO4)(39.998 grams/1 mole NaOH) = 4.0 grams NaOH needed =================
How many grams of sulfuric acid will neutralize 10.0 g of sodium hydroxide?
Balanced equation. H2SO4 + 2NaOH >> Na2SO4 + 2H2O 10 grams NaOH (1mol NaOH/39.998g )(1mol H2SO4/2mol NaOH )(98.086g H2SO4/1molH2SO4 ) = 12.26 grams of H2SO4
How many ml of 250 M NaOH are required to neutralize 30.4 ml of 152 M HCl?
M1V1=M2V2... By plugging in, you get 18.48 mL of NaOH
How many moles of sodium hydroxide are required to neutralize 20 mol of nitric acid?
20 moles of NaOH needed to neutralize 20 moles of nitric acid
How many milliliters of 0.400 M NaOH are required to completely neutralize 20.00 mL of 0.200 M HCl?
10 mL
How many moles of NaOH are present in 20ml of 0.5M NaOH?
M = g/L 20 = g/0.05 20 * .05 = g 1.0 = g of solute
How many NaOH required to neutralize complitly4.9 gms of H2SO4?
Grams NaOH?? Balanced equation. 2NaOH + H2SO4 --> Na2SO4 + 2H2O 4.9 grams H2SO4 (1 mole H2SO4/98.086 grams)(2 mole NaOH/1 mole H2SO4)(39.998 grams/1 mole NaOH) = 4.0 grams NaOH needed =================
How many ml of 6.0 N NaOH is required to neutralize 30 ml of 4 N HCL?
formula for neutralizatrion is volume of acid X normality of acid = volume of base X normality of base so (0.3)(3) should equal (4)(volume) which is .225L. However, Ca(OH)2 contains 2 moles of OH resulting division of total volume needed by 2. Thus, the answer becomes .1125L or 112.5ml.
How many grams of sulfuric acid will neutralize 10.0 g of sodium hydroxide?
Balanced equation. H2SO4 + 2NaOH >> Na2SO4 + 2H2O 10 grams NaOH (1mol NaOH/39.998g )(1mol H2SO4/2mol NaOH )(98.086g H2SO4/1molH2SO4 ) = 12.26 grams of H2SO4
How many potassium ions are required to neutralize a nitride ion?
3 ions
A nitric acid soulution is neutralized using sodium hydroxide how many grams of sodium hydroxide are needed to neutralize 2.50 L of 0.800 M Nitriric acid soulution?
Balanced equation first. HNO3 + NaOH >> NaNO3 + H2O Now, Molarity = moles of solute/volume of solution ( find moles HNO3 ) 0.800 M HNO3 = moles/2.50 Liters = 2 moles of HNO3 ( these reactants are one to one, so we can proceed to grams NaOH ) 2 moles NaOH (39.998 grams NaOH/1mole NaOH) = 79.996 grams of NaOH need to neutralize the acid. ( you do significant figures )
How many moles of NaOH will it take to neutralize 0.61 L of 0.46 M HCl?
1st Get the balanced equation NaOH + HCl -> NaCl + H2O Find the number of moles in HCl; n = cv n = 0.46x0.61 n = 0.2806 moles the number of moles of HCl and NaOH is the same so 0.2806moles will be needed
How many moles of NaOH are needed to prepare 2 liters of a 2.0 M solution?
4 moles or 160 g NaOH is required for one litre solution.
How many milliliters in 0.02l?
20ml
