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If 5y-4 10 plus 11 find the value of y?
x + 5y = 10 5y = -x + 10 y = -x/5 + 2 m = -1/5 or .2
4x + 3y + 3 = 4 ----> 4x = 1 - 3y ----> x = 0.25 - 0.75y ----> 3y = 1 - 4x ----> y = (1/3) - (4/3)x
y = 2x+5 x+y = 4 Substitute the value of y into the second equation: x+2x+5 = 4 x+2x = 4-5 3x = -1 Divide both sides by 3 to find the value of x: x = -1/3 Substitute the value… of x into the original equations to find the value of y: x = -1/3 and y = 4 and 1/3
2y+5y=10 7y=10 y=10/7
Find the illegal values of c in the multiplication statement c2-3c-10 over c2 plus 5c-14 by c2-c-2 over c2-2c-15?
5y+8=7y subtract 5y from each side , 5y+8=7y -5y -5y 8=2y /2 /2 4=y
5y+8=7y 2y=8 y=4
With difficulty because the discriminant of the quadratic equation is less than zero meaning it has no solutions