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If A 100 kg object is pulled vertically upward 5.0 m by a rope with an acceleration of 1.0 ms2 Find the work done by the tension force in the rope?
Abhi007nav
Tension in the rope needed to pull the object of mass 100 kg with an acceleration of 1 m/s^2 is 100 N. Since the force is the product of mass and acceleration. So 100 x 1.0 = 100 N
With this force of 100 N the body is moved through a distance of 5.0 m and hence work done will be 500 joule. Since the formula for the work done is F s cos @
Here F = 100 N ; s = 5.0 m ; @ = 0 as tension and the displacement in the same direction. Hence the value of work done is 500 joule.
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