Yes.
If x is not divisible by 3 then x leaves a remainder of 1 or 2 when it is divided by 3. That is, x is of the form 3y+z where z = 1 or 2.
Then x2 = (3y+z)2 = 9y2 + 6yz + z2 = 3(3y2 + 2yz) +...
of course it is! just because its a negative number doesnt mean its not divisible. any number is divisble by itself and the answer is always 1. in this case the answer is negative 1 because the...