All the F1 will have wire hair.
The reason:A homozygous wire-haired dog must be SS. It must have at least one S allele if it shows the dominant character, and "homozygous" means pure-breeding, so there is no other allele present.
A smooth-haired dog must be ss. Any organism displaying a recessive trait must be homozygous, as a dominant allele would mask the recessive one.
So the cross is:
SS x ss
and one parent must pass on the S gene, one the s. Therefore all the F1 must be Ss. Their phenotype is wire-haired, because they have a dominant allele, but they are all heterozygous, because they inherited a recessive gene from the smooth-haired parent.
This cross demonstrates Mendel's First Law.
What is the genotype and phenotype of the F1 generation
The genotype AA represents a homozygous dominant genotype. The capital letter "A" represents the dominant allele, while the lowercase letter "a" would represent the recessive allele. If both dominant alleles are present in a genotype (homozygous dominant) then the phenotype is "A" phenotype. If one dominant allele and one recessive allele are present (heterozygous dominant) then the phenotype is "A". Finally, if both recessive alleles "a" are present (homozygous recessive) then the phenotype is "a". Therefore, the answer to your question is the genotype AA would result in an "A" phenotype because the genotype is homozygous dominant.
The phenotype pairings which the genotypes of individuals be directly known are homozygous recessive.
incomplete dominance
Yes, homozygous with homozygous (both the same genotype) will produce homozygous of the same genotype
What is the genotype and phenotype of the F1 generation
All of the F1 generation are heterozygous, therefore 100% exhibit the dominant phenotype. The F2 generation has a ratio of 1 homozygous dominant: 2 heterozygous: 1 homozygous recessive. This results in a phenotypic ratio of 3 dominant: 1 recessive.
All of the F1 generation are heterozygous, therefore 100% exhibit the dominant phenotype. The F2 generation has a ratio of 1 homozygous dominant: 2 heterozygous: 1 homozygous recessive. This results in a phenotypic ratio of 3 dominant: 1 recessive.
homozygous dominant is the genotype. hypothetically, if the gene was for the color purple in a flower, the phenotype would be purple, while the genotype would be homozygous dominant AKA Pp.
The same phenotype as both of the parents.
Given those conditions, the offspring have a 50% chance of demonstrating the dominant phenotype and a 50% chance of demonstrating the recessive phenotype.
Straight thumbs, hitch hiker's thumb is recessive...so the F1 generation in this example would be heterozygous and have the dominant (straight thumbed) phenotype.
The phenotype (as I assume would be colour) for both homozygous and heterozygous yellow-grained corn is yellow.
Homozygous dominant and heterozygous both are a dominant phenotype.
It's expressed when a heterozygous phenotype is between two homozygous phenotypes.
The genotype AA represents a homozygous dominant genotype. The capital letter "A" represents the dominant allele, while the lowercase letter "a" would represent the recessive allele. If both dominant alleles are present in a genotype (homozygous dominant) then the phenotype is "A" phenotype. If one dominant allele and one recessive allele are present (heterozygous dominant) then the phenotype is "A". Finally, if both recessive alleles "a" are present (homozygous recessive) then the phenotype is "a". Therefore, the answer to your question is the genotype AA would result in an "A" phenotype because the genotype is homozygous dominant.
100 percent.