Iron(III) bromide is an ionic compound.
It is covalent (molecular)
Molecular
Molecular.
Molecular
CO is molecular
The molecular mass of CBr4 is 12.0 + 4(79.9) = 331.6Amount of CBr4 = mass of substance / molecular mass = 393/331.6 = 1.19mol This means that a 393g pure sample contains 1.19 moles of tetrabromomethane. The Avogadro's number is 6.02 x 10^23 So, number of molecules of CBr4 = 1.19 x 6.02 x 10^23 = 7.13 x 10^23
Molecular because it is between 2 non-metals.
Molecular
CH3OH is molecular.
Yes it is molecular (or covalent) compound
No, it is not.
No CBr4 is covalent.
Tetrahedral
No, CBr4 is a covalent compound.
Is BO ionic or a molecular
CO is molecular
The molecular mass of CBr4 is 12.0 + 4(79.9) = 331.6Amount of CBr4 = mass of substance / molecular mass = 393/331.6 = 1.19mol This means that a 393g pure sample contains 1.19 moles of tetrabromomethane. The Avogadro's number is 6.02 x 10^23 So, number of molecules of CBr4 = 1.19 x 6.02 x 10^23 = 7.13 x 10^23
It is ionic because chromium is a metal.
HCIO4 is an ionic compound.
Ionic Molecular
Molecular because it is between 2 non-metals.