First we assume that all of them were worth the same number of credits. If that is the case then it will be at least 2.25 it could by higher.
The GPA of 2 B's a B- and a D can be equal to 2.425.
That is obviously failing. On a 4 point scale that is a 1.25.
Its actually a B-
A 2.5 would be an average of Bs and Cs. To determine your GPA, let A =4, B = 3, C =2, and D=1. Add up your grades and divide by the number of classes to give you an average (your GPA).
On a GPA scale where A = 4 B = 3 C = 2 and D = 1 then the GPA is (4 + 4 + 4 + 1 + 2 + 2 + 2) divided by 7 = 2.71
If an A = 4 you have (3 + 2 + 2 +1)/4 = 8/4 = 2.0 GPA
A C grade is equal to 2 GPA and a D grade is around 1.5 GPA. So you can calculate and find the average.
On a scale for GPA where A =4,B=3,C=2, and D=1 then GPA = (4 x2) + (3 x 3) + (2x2) all divided by 7 to get average GPA = 3.0
That is a C average. D is 1, C is 2, B is 3, A is 4
A GPA of 1.0 is equivalent to a D. In order to graduate, you will need to significantly improve your GPA.
If all 7 of those courses have equal weights, then on a four-point system, that is a GPA of 2.857 .
That is a little bit above a C 4 = A 3 = B 2 = C 1 = D
It equals to a low B 4 = A 3 = B 2 = C 1 = D 0 = F
2.83 based on A=4, B=3, C=2, D=1. If each class has the exactly the same number of credits, then this would be a B+.
Lots. A = 4; B = 3; C = 2; D = 1; F =0. So if one had an A, a C, and a B, their GPA would be 3.0 (B)