Answers.com > Wiki Answers > Categories > Cars & Vehicles > Asian Cars > Honda > Honda Prelude > Let Sn be the group of permutations on n symbols Then 1. S4 has no subgroup isomorphic to S3 2. S4 has only one subgroup isomorphic to S3 3. S4 has exactly 3 distinct subgroups isomorphic to S3?

Let Sn be the group of permutations on n symbols Then 1. S4 has no subgroup isomorphic to S3 2. S4 has only one subgroup isomorphic to S3 3. S4 has exactly 3 distinct subgroups isomorphic to S3?

Answer:
It has 4 subgroups isomorphic to S3. If you hold each of the 4 elements fixed and permute the remaining three, you get each of the 4 subgroups isomorphic to S3.
First answer by ID1111699000. Last edit by ID1111699000. Question popularity: 1 [recommend question].

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