What were the four parties of election of 1860?

Answer 1

The four candidates (and their parties) running for president in 1860 were Abraham Lincoln (Republican), Stephen Douglas (North Democrat), John Breckinridge (South Democrat), and John Bell (Constitutional Union). The winner was Abraham Lincoln.

Answer 2

The Republicans fielded ex-Congressman Abraham Lincoln and Senator Hannibal Hamlin. The northern faction of the Democratic Party fielded Senator Stephen Douglas. The southern faction of the Democratic Party fielded Vice-President John C. Breckenridge. And the remains of the Whig Party (The Constitutional Party) fielded John Bell.

Answer 3

The four parties in the election of 1860 were the Republican Party, the Southern Democratic Party, the Constitutional Union Party, and the Democratic Party. Abraham Lincoln of the Republican Party won with 180 electoral votes.

Answer 4

The four Presidential nominees for the 1860 US Presidential election were:

• Abraham Lincoln - Republican
• John C. Breckinridge - Southern Democratic
• John Bell - Constitutional Union
• Stephen A. Douglas - Northern Democratic

Abraham Lincoln won the election, carrying 18 of 33 states.

Answer 5

The four candidates in the U.S. presidential election of 1860 represented the...

• Republican Party (Abraham Lincoln)
• Northern Democratic Party (Stephen A. Douglas)
• Southern Democratic Party (John C. Breckinridge)
• Constitutional Union Party (John Bell)

Answer 6

Abraham Lincoln , Stephen Douglas , john Breckinridge and john bell