0
#include <stdio.h>
void main()
{
int digi,num,i,sum=0;
printf("Enter the number of digits:");
scanf("%d",&num);
while(i>0);
{
for(i=0;i<10000;i++)
{
digi=num;
i=digi%10;
sum=sum+i;
num=digi/10;
}
printf("The sum of digits entered is %d",sum);
}
}
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How do you write an assembly language program to find the sum of n numbers using array?
write an assembly language program to find sum of N numbers
Write a Shell program to find the sum of cube of individual digits of a number?
no thanks
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There are many shell programs that will find the sum of the square of individual digits of a number. A small example is: SD=3n=2, sum=2, and SD=2.
How do you find the sum of digits of each number?
Add the digits together. The sum of the digits of 23 is 5.
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Shell problems are programs that can be run to find out information about numbers. The problem can help find an even or odd number, or what the sum of a cube is.
What does find the sum of the digits of each number above mean?
Add the digits together. The sum of the digits of 23 is 5.
Write a java program to find out the sum of a number of n digits?
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C program to find the sum of the digits of a number?
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What is the sum of the digits from 1 to 100?
5050, according to the program I quickly whipped up.
Find the sum of the digits in the smallest positive integers that is divisible by 2 and 4 and 6 and 10 and 12 and 14?
The sum of the digits is 6.
Algorithm for to find sum of individual digits of a positive integer?
enter the number whose digits are to be added num is the given value num=0! k=num%10 sum=sum=k k=num/10 num=k print the sum of the digits
Program in c language to find sum of digits using recursion?
# includevoid main(){int no,rem=0,sum=0,n; /*declaration*/printf("Enter 2 digit number:");scanf("%d",&no);for(n=1;n
