Reverse a string in C language?

Answer 1

/* To reverse the given string using pointer By $ */

#include <stdio.h>

#include <string.h>

void main ()

{

char str[15];

char rev[15];

int i;

int count;

char* p;

gets(str);

count = strlen(str);

p = rev + strlen(str)-1;

for(i = 0; i < count; i++)

{

*(p - i) = *(str + i);

}

rev[count]='\0';//in some compilers it may show error show u can make it NULL

/* verify results */

printf("Original string: %s\n",str);

printf("Reversed string: %s\n",rev);

}

Answer 2

#include<stdio.h>

#include<string.h>

#include<conio.h>

void main()

{

int num,i,j,result,index;

char name[25][25],temp[25];

clrscr();

printf("\nNumber of names to be sorted in descending order\n");

scanf("%d",&num);

printf("Enter %d names to be sorted\n",num);

for(i=0;i<num;i++)

scanf("%s",name[i]);

for(i=0;i<num;i++)

{ index=i;

for(j=i+1;j<num;j++)

{

result=strcmp(name[index],name[j]);

if(result<0)

index=j;

}

strcpy(temp,name[index]);

strcpy(name[index],name[i]);

strcpy(name[i],temp);

}

printf("\nNames Sorted in Descending Order\n");

for(i=0;i<num;i++)

{

printf("\t%s",name[i]);

}

}

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Answer 3

reverse (char *p) { char c, *p1, *p2;

if (strlen(p) <= 1) return; for (p1=p, p2=p+strlen(p)-1; p1<p2; c=*p1, *p1=*p2, *p2=c, p1++, p2--); }

Answer 4

reverce input show