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The critical angle for a certain liquid-air surface is 21 degrees. Determine the index of refraction of the liquid and the speed of light in the liquid.?
Wiki User
∙ 14y ago
Refractive index=Sin i divided by Sin r where r= angle of refraction
i= angle of incidence
Light rays hitting the boundary at an angle of 23° is refracted at 90° to the normal. Therefore, r= 90 and Sin 90° = 1 . This implies that Refractive index= Sin i
=Sin21°
= 0.36
Speed of light in liquid= Speed of light in air divided by refractive index
= 300000000 Divided by 0.36
= 833333333.3 m/s
Wiki User
∙ 14y ago
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