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Mg(OH)2 --> Mg2+ + 2 OH - Each mole of magnesium hydroxide gives 1 mole of mamgnesium ions and 2 moles of hydroxide ions. Therefore, Ksp = [Mg2+] [2 OH -]2 Let solubility of magnesium hydroxide be s. Therefore, we get s as the concentration of magnesium ions and (2s)2 as the solubility of hydroxide ions. s = 1.4 X 10-4 M Therefore, Ksp = s (2s)2 = 4s3 Substituting the value of s, we get Ksp = 1.09 X 10-11

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16y ago
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15y ago

to find the Ksp you look it up in your RDC.

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Q: The molar solubility of magnesium hydroxide MgOH2 in water is 1.4 x10-4M. What is the Ksp of magnesium hydroxide?
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