Mg(OH)2 --> Mg2+ + 2 OH - Each mole of magnesium hydroxide gives 1 mole of mamgnesium ions and 2 moles of hydroxide ions. Therefore, Ksp = [Mg2+] [2 OH -]2 Let solubility of magnesium hydroxide be s. Therefore, we get s as the concentration of magnesium ions and (2s)2 as the solubility of hydroxide ions. s = 1.4 X 10-4 M Therefore, Ksp = s (2s)2 = 4s3 Substituting the value of s, we get Ksp = 1.09 X 10-11
to find the Ksp you look it up in your RDC.
magnesium thiotellurite
MgCl2(aq) + 2KOH(aq) --> Mg(OH)2(s) + 2KCl(aq)It is the molar ratio in the equation. Every mole of magnesium chloride requires 2 moles of potassium hydroxide. Thus 3 moles would need 6 moles of alkali for complete reaction. We don't have that much, so potassium hydroxide is the limiting reactant and we can only use 2 moles of the magnesium chloride and produce 2 moles of magnesium hydroxide.
Mg(OH)2 = 24.31 + (16.00 + 1.008)x2 = 24.31 + (17.008)x2 = 24.31 + 34.016) = 58.326 = 58.33 g/mol
Sodium has a molar mass of 23 Hydroxide (Hydrogen & Oxygen) have a molar mass of 17 23+17=40g/mol 40grams per mole
it is insoluble in an aqueous solution.
no
not sure exactly, but it has magnesium, oxygen and iodine
MgCl2(aq) + 2KOH(aq) --> Mg(OH)2(s) + 2KCl(aq)It is the molar ratio in the equation. Every mole of magnesium chloride requires 2 moles of potassium hydroxide. Thus 3 moles would need 6 moles of alkali for complete reaction. We don't have that much, so potassium hydroxide is the limiting reactant and we can only use 2 moles of the magnesium chloride and produce 2 moles of magnesium hydroxide.
magnesium thiotellurite
the molar mass of sodium hydroxide is 40g/mol mike
Mg(OH)2 = 24.31 + (16.00 + 1.008)x2 = 24.31 + (17.008)x2 = 24.31 + 34.016) = 58.326 = 58.33 g/mol
Sodium has a molar mass of 23 Hydroxide (Hydrogen & Oxygen) have a molar mass of 17 23+17=40g/mol 40grams per mole
Molar mass of the hydroxide anion, OH-, is 17.00734 g/mol
the molar mass of potasium hydroxide is 56 g/mole
48.5g/l
it is insoluble in an aqueous solution.
3