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The number of Au atoms in 1.5g of Au is?

In: Science, Chemistry [Edit categories]

Answer:

n(Au)= 1.5g/M(Au)
= 1.5/196.97 = 0.00761537mol

n(Au) = No(Atoms)/N(a)
therefore N(Atoms)=n(Au) x N(a)
N(atoms) = 0.00761537mol x 6.02x10^23mol*-1

N(atoms) approximatly equals 4.6x10^21 atoms

First answer by Dean14159. Last edit by Dean14159. Contributor trust: 0 [recommend contributor ]. Question popularity: 1 [recommend question].

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Find moles of Au in 2.88X1023 atoms of Au?
1 mol = 6.02 x 10^23 2.88 x 1023 atoms = 2946.24 atoms = (2946.24) / (6.023 x 10^23) moles = 4.89 x 10^-21moles Or if you meant=> 2.88 x 10^23 atoms = (2.88/6.02) moles = 0.478 moles (3 s.f)
What atomic number is Au or Gold?
79
What is atomic number for Au?
79
What is the atom charge of Au?
The charge of Au is either 1+ or 3+.
What is AU?
AU is an abbreviation for a number of things. It can refer to Australia, the Angstrom Unit, the Astronomical Unit, and the Arithmetic Unit. In addition, it can refer to Auburn University and Air...