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If the ratio is 16:9, call the horizontal edge A and the vertical edge B. A=16x, B=9x. For a rightangled triangle, A2+B2=702. So (16x)2 + (9x)2 = 4900. From here: (16x)2 + (9x)2 = 4900 256x2 + 81x2 = 4900 337x2 = 4900 x2 = 4900/337 = 14.51 x = 3.82 inches Backsubbing: A = 16 * 3.82 = 61.12 inches, B = 9 * 3.82 = 34.38 inches.

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14y ago
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14y ago

Dude, that's one seriously humungous TV!

Applying pythagoras:

2002 = (16x)2 + (9x)2 = 337x2

Thus x = sqrt(2002/337) = sqrt(40000/337) = sqrt(118) = 11

So

Width = 16x = 176in
Height = 9x = 99in

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Q: The ratio of width to the height of the screen of an HDTV is 16 to 9 suppose a large screen HDTV has a 70-in diagonal screen find the width and the height of the screen?
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