Using combinatorics calculate the number of factors of 2310?

An easy way to calculate all the factors of whole numbers is to iterate from 1 to that number and check if the remainder is zero using the "%" operation. def getFactors(num): """Return the factors of...

If there was, we would have known. The only way I could think of is using a graphing calculator and use y=(the number you want factored)/x and go to table and there should be the x and y values,...

int factorial(int n) { int total = 1; for(; n > 1; n--) total *= n; return total; }

A complex number a + bi, can be represented as a 2x2 matrix: [a -b] [b a ] or [a b ] [-b a ] , just keep the same notation throughout your work. See the wikipedia article on Complex Numbers, and the...

A composite is any number that has a prime factor smaller than itself and greater than 1.