If my math is right, and it probably isn't, there's approximately a 0.00000013% chance. Here is the math one might consider: Essentially you are looking to deal 8 cards out of a 52 card deck, order being irrelevant.
So that would be 52!/{(52-8)! * (8)!} = 752,538,150 possibilities And you are looking for ONE of those possibilites 1 / 752,538,150 = 0.000000001328836285575690 So as a percentage, 0.00000013% would seem correct.
In a standard deck of 52 cards, there are 4 aces and 4 queens, so the probability of picking an ace or queen is 8 in 52, or 2 in 13, or about 0.1538.
16% chance
On one random draw, the probability is 2/13.
The probability of drawing a queen, king, or ace from a standard deck of 52 cards is 12 in 52, or 3 in 13, or about 0.2308.
The probability of drawing an Ace, King, and Queen from a standard deck of 52 cards, with replacement, is (4 in 52)3 or 64 in 140608, or 1 in 2197, or about 0.0004552.
The probability of picking a black ace in one random draw from a normal pack of playing cards is 1/26.
If you pick enough cards, the probability is 1.
12/52 = 3/13 = 0.2307... ≈ 23.08%
The probability of drawing an Ace from a standard deck of 52 cards is 4 in 52, or 1 in 13, or about 0.07692.
The probability of drawing a jack, queen, or king on the second draw if the first draw was an ace (without replacement) is (4 + 4 + 4) in (52 - 1) or 12 in 51, which is 4 in 17, or about 0.2353.
The probability of pick a red ace out of a standard deck of cards would be 1/26 because there are two read aces, the ace of diamonds and the ace of hearts.
there are 4 1's or aces in a pack of 52 cards. Probability of picking an ace=4/52=1/13