This is a double displacement reaction. Abstractly, these reactions could be described in the following manner:
AB + CD --> AD + BC
Therefore, a neutralization reaction would look like this:
HCl + NaOH --> NaCl + H-OH
In other words, a neutralization reaction will always form water and a salt.
No colour forms.
All four compounds of this reactiuon are 'colourless'.
Since Iodine is less reactive than chlorine, iodine will be displaced.
Hence, solution turns yellowish-brown.
when HCl and NaOH neutralize each other, H2O and NaCl are formed
The chemical reaction is:
Na2CO3 + 2 HCl = 2 NaCl + H2O + CO2
it remains colorless..
NaOH is a white solid.
NaCl + H2O
NaOH and HCl
The product is sodium chloride.The reaction is:NaOH + HCl - NaCl + H2O
There will be no reaction of Hexane as it does'nt have any reactive sites. Hexene will react only with Hcl as the double bond is nucleophilic to give poly chlorinated hexane. Hexene will not react with NaOH
Water plus a salt eg caustic soda + hydrochoric acid NaOH + HCl -> H2O + NaCl Some of these reactions can be explosive, so don't try it
NaCl + H2O
NaOH and HCl
The product is sodium chloride.The reaction is:NaOH + HCl - NaCl + H2O
There will be no reaction of Hexane as it does'nt have any reactive sites. Hexene will react only with Hcl as the double bond is nucleophilic to give poly chlorinated hexane. Hexene will not react with NaOH
Water plus a salt eg caustic soda + hydrochoric acid NaOH + HCl -> H2O + NaCl Some of these reactions can be explosive, so don't try it
HCl is an acid which reacts with NaOH a base to produce H2O water and a salt - in this case NaCl HCl + NaOH = NaCl + H2O
An acid (HCl) added to an alkali/base (NaOH) forms a salt (NaCl) and water : HCl + NaOH ----> NaCl + H2O
HCl + NaOH -----> NaCl + H2O
Zinc is a metal. However, because with HCl it forms ZnCl2 and with NaOH it forms Na2ZnO2 it is classed as amphoteric.
The reactants are HCl and NaOH.
The reactants are NaCl and H2O. A becks: HCl NaOH
Balanced equation. NaOH + HCl -> NaCl + H2O all one to one. find moles HCl. 11 grams HCl (1 mole HCl/36.458 grams ) = 0.3017 moles HCl Moles HCl same as moles NaOH Molarity = moles of solute/Liters of solution 1.06 M NaOH = 0.3017 moles NaOH/liters of solution = 0.2846 Liters this is equal to..... 285 milliliters of NaOH needed