it is contact force
Calculate drag coefficient of freefaller (prior to chute opening) > (constant) force down (in newtons) due to gravity = mass * acceleration due to gravity, say 80 * 10 = 800 …newtons. > The up force (newtons) = velocity2 * drag coefficient > At terminal velocity (where up and down forces balance) the up force = 800 newtons, say terminal velocity = 70 metres / second > 800 = 4900 * drag coefficient > Drag coefficient = 800 / 4900 > Drag coefficient = 0.163
First of all, gravity is not a force, it is an acceleration. What you mean is the force of weight, which is the acceleration of gravity multiplied by mass (all forces are vect…ors, and gravity is not a vector.) When air resistance is subtracted from weight, you have the net force on a falling object (assuming those are the only forces acting on it.)
Yes. It falls under the category of drag force. Drag force is the force that resists the motion of a body.
It requires a force to propel an object through air, because of the air resistance. Normally, if there were no air resistance and the object were being propelled on the le…vel with no friction, a constant force would accelerate the object steadily. However, it would require a steady force to propel the object through air even without acceleration. And the faster it went the more resistance it would meet.
Air resistance is a friction force, the flow of air over a surface will cause friction and produce drag. Thanks
= the (square of the velocity (m/s) * drag coefficient ) newtons if terminal velocity is known (forces balanced , no further acceleration), drag coefficient can be found. …say terminal velocity(tv) = 70 m/s, acceleration due to gravity(g) = 9.8 m/s^2, mass(m) = 80kg m * g (force down) = tv^2 * drag coefficient (force up) at terminal velocity then m * g / tv^2 = drag coefficient 80 * 9.8/4 900 = 0.16
No it is a non conservative force
The net force on a following object
Air resistance can be roughly translated as drag or friction of the wind causing something to slow down.