During the Vietnam War there were the following classifications: Class 1, 2, 3, and 4. 1-A, 1-A-O, 1-C, 1-D, 1-H, 1-O, and 1-W. 2-A, 2-C, 2-D, and 2-S. 3-A. 4-A, 4-B, 4-C, 4-D, 4-F, 4-G, and 4-W. 1-A meant the man was available for military service. 1-W meant he was a Conscientious Objector. 4-F meant the man was unfit for military service.
During the Vietnam War there were the following classifications: Class 1, 2, 3, and 4. 1-A, 1-A-O, 1-C, 1-D, 1-H, 1-O, and 1-W. 2-A, 2-C, 2-D, and 2-S. 3-A. 4-A, 4-B, 4-C, 4-D, 4-F, 4-G, and 4-W. 1-A meant the man was available for military service. 1-W meant he was a Conscientious Objector. 4-F meant the man was unfit for military service.
y means you and 1 means you get that person
First substitute the coordinates of (x1, y1) into the equation, then simplify the equation so it has y in terms of x. y - y1 = m(x - x1) y - y1 = mx - mx1 y = mx - mx1 + y1 y = mx + (y1 - mx1) y = mx + (C)
If you mean: (y2-y1)/(x2-x1) and (y1-y2)/(x1-x2) then either works out the same.
Each element is the mean of the corresponding elements. Thus, the mean of (x1, y1) and ( x2, y2) is [( x1 + x2)/2, (y1 + y2)/2]
There are many calculations that could be done: =SUM(Y1:Y10) =AVERAGE(Y1:Y10) =MAX(Y1:Y10) =MIN(Y1:Y10) =COUNT(Y1:Y10)
If you mean: 3x-y = 1 then it is a straight line equation
5x-y1 = 4
for a linear function m= rise/ run if given 2 points on the graph m= (y2-y1)/(x2-x1) remember to simplify (lowest terms)! the 2 behind the x and the y is are not exponents! They mean the range in the second bracket: ex. (5,6)<--- 6= x2 5= x1 (7,8) <--- 8= y2 7=y1
It shows the relationship of y in terms of x. [y = (yIntercept) + ((slope)*(x))] [slope = (y2 - y1)/(x2 - x1)]
GIven 2 distance points (x1,y1) and (x2,y2) we can draw a line between those point and the midpoint formula finds the midpoint of that line. Call the midpoint (m1,m2) then it is [ (x1+x1 )/2 , (y1+y2/2)]
#include<stdio.h> #include<graphics.h> #include<math.h> #include<conio.h> #include<dos.h> #include<alloc.h> #include<stdlib.h> #define RAD 3.141592/180 class fig { private: int x1,x2,y1,y2,xinc,yinc; public: void car() { xinc=10;yinc=10; x1=y1=10; x2=x1+90;y2=y1+35; int poly[]={x1+5,y1+10,x1+15,y1+10,x1+20,y1,x1+50,y1,x1+60,y1+10,x1+90,y1+17,x1+90,y1+20,x1+5,y1+20,x1+5,y1+10}; setfillstyle(SOLID_FILL,LIGHTGRAY); setlinestyle(SOLID_LINE,1,2); setcolor(4); drawpoly(9,poly); line(x1+15,y1+10,x1+60,y1+10); line(x1+20,y1+10,x1+20,y1); line(x1+35,y1+10,x1+35,y1); line(x1+50,y1+10,x1+50,y1); floodfill(x1+18,y1+8,4); floodfill(x1+28,y1+8,4); floodfill(x1+36,y1+8,4); floodfill(x1+52,y1+8,4); setfillstyle(SOLID_FILL,4); floodfill(x1+18,y1+12,4); setfillstyle(SOLID_FILL,BLUE); bar(x1+5,y1+20,x1+90,y1+25); setcolor(DARKGRAY); circle(x1+20,y1+25,8); circle(x1+20,y1+25,6); setfillstyle(1,8); floodfill(x1+21,y1+25,8); circle(x1+70,y1+25,8); circle(x1+70,y1+25,6); floodfill(x1+71,y1+25,8); int size=imagesize(x1,y1,x2,y2); void far *buf=farmalloc(size); getimage(x1,y1,x2,y2,buf); while(!kbhit()) { putimage(x1,y1,buf,XOR_PUT); x1+=xinc;x2+=xinc; if(x2<(getmaxx()-10)) putimage(x1,y1,buf,COPY_PUT); else { cleardevice(); x1=10;x2=x1+90; y1+=yinc;y2+=yinc; if(y2<(getmaxy()-10)) { putimage(x1,y1,buf,COPY_PUT); } else {y1=10;y2=y1+35;} } delay(200); } farfree(buf); getch(); } } } } void main() { int gd=DETECT,gm; initgraph(&gd,&gm,"d:\\cplus"); fig f; f.car(); cleardevice(); closegraph(); }
Line (x1, y1, x2, y1); Line (x2, y1, x2, y2); Line (x2, y2, x1, y2); Line (x1, y2, x1, y1);
{3x +y =1 {x+y= -3