A 2p electron
Outer electron on a boron atom.
Type your answer here... A 3s electron
ml = -1
Assuming you mean the set of quantum number describing the VALENCE electrons of aluminum, they would ben = 3l = 1ml = -1s = +1/2Of course, since Al has only 1 p electron, ml could also have been 0 or +1 and s could have been -1/2
The quantum number set of the ground-state electron in helium, but not in hydrogen, is (1s^2) or (n=1, l=0, ml=0, ms=0). It indicates that the electron occupies the 1s orbital, which has a principal quantum number (n) of 1, an orbital angular momentum quantum number (l) of 0, a magnetic quantum number (ml) of 0, and a spin quantum number (ms) of 0.
They act as codes that provide information about each electron in an atom. n - energy level (can be 1,2,3…) l - orbital shape (s=0, p=1, d=2) ml - orbital orientation (goes from -/to +/by integers) ms - spin (arrow up or down, and can be either +½ or -½)
There are 4 quantum numbers that specify the quantum system. n is the energy level, l is the angular momentum, ml is the projection of angular momentum, ms is the spin projection.
A 3s electron
A 4d electron; that is for apex :)
ml = -1
ml = -1
n=3 l=1 ml=1 ms=-1/2
A 3s electron
No, for any given electron, the principle quantum number will be larger. For example, a second shell, p-subshell electron will have the quantum numbers {2, 1, ml, ms} where mlcan be -1, 0, or 1 and, as always, ms can be ½ or -½. The largest ml can be is +1, which is smaller than the principle quantum number, 2.
Assuming you mean the set of quantum number describing the VALENCE electrons of aluminum, they would ben = 3l = 1ml = -1s = +1/2Of course, since Al has only 1 p electron, ml could also have been 0 or +1 and s could have been -1/2
ml=0
ml = 0
The quantum number set of the ground-state electron in helium, but not in hydrogen, is (1s^2) or (n=1, l=0, ml=0, ms=0). It indicates that the electron occupies the 1s orbital, which has a principal quantum number (n) of 1, an orbital angular momentum quantum number (l) of 0, a magnetic quantum number (ml) of 0, and a spin quantum number (ms) of 0.
It's the azimuthal quantum number. It specifies the angular momentum of the orbital, which can broadly speaking be thought of as its "shape." (The reason I'm putting that in quotation marks is that it's possible for two orbitals with the same azimuthal quantum number to appear rather different in overall shape.)