It depends on the volume, if we consider 1 liter of the solution 500 mg of sodium chloride is needed.
The formula of sodium chloride is NaCl; therefore, the gram formula mass of sodium chloride is the sum of the gram atomic masses of sodium and chloride, or 58.443, to the justified number of significant digits. The number of gram formula masses in 23.376 grams is therefore 23.376/58.443 or 0.399998, to the justified number of significant digits.
From the law of conservation of mass: 58.5 - 23 = 35.5 grams of chlorine required. Interestingly, 23 and 35.5 are approximations to the gram atomic masses of sodium and chlorine respectively.
39.34
The answer is 59,5 g Na.
500 mg of sodium is equivalent to 0.5 gram of sodium, which in turn is equivalent to around 1.27 gram of common table salt (sodium chloride).
0g as it contains only sodium and chloride
calcium chloride
79,9 g NaCl is equivalent to 1,367 moles.The formula mass of the compound sodium chloride, NaCl is 23.0 + 35.5 = 58.5Amount of NaCl = 79.9/58.5 = 1.37molThere are 1.37 moles of sodium chloride in a 79.9 gram pure sample of the compound.
Sodium has an atomic weight of 22.99 g/mol. Chlorine has an atomic weight of 35.45 g/mol. NaCl has an atomic weight of 58.44 g/mol. Therefore 92g of sodium would yield 233.86g of sodium chloride (NaCl).
By definition, there are 1000 milligrams in each gram. Therefore, in 12 grams of anything there are 12,000 milligrams.
Because 7.5% NaCl agar inhibits gram negative organisms from growing, and is "selective" in that only gram positive organisms can grow in this type of agar.
One gram mole of common table salt, Sodium Chloride (NaCl) weighs 58.45 gm.