it will pop
Cold air is denser than warm air, therefore a balloon filled with cold air will weigh more than an identically sized balloon full of warm air. This extra weight causes the balloon to sink bellow warmer air. Cold air is denser than warm because as molecules become cooler they move more slowly causing them to be closer together.
it becomes a mixture of a warm and cold water :)))
Nothing happens to the mass of the balloon. Mass is conserved, so the temperature of the balloon will not affect it's mass. Mass can be thought of the amount of "stuff" that makes up a balloon. It can be obtained by adding up the mass of all the molecules of rubber in the balloon. Obviously, putting the balloon in a warm room will not change the number of molecules in the balloon, therefore the mass stays constant. The volume of the balloon will probably increase. Because volume increases but mass remains constant, the density of the balloon would decrease. D = m/v
Yes, because your breath is warm.
it would shrink in cold and expand in warm, if you really want to surprise your teacher say it has to do with particle theory
the balloon will inflate
it sinks
Cool breeze flows when this happens. The water vapor then condenses.
Cold air is denser than warm air, therefore a balloon filled with cold air will weigh more than an identically sized balloon full of warm air. This extra weight causes the balloon to sink bellow warmer air. Cold air is denser than warm because as molecules become cooler they move more slowly causing them to be closer together.
the warm water floats
The air inside expands.
it would pop
Cold water doesn't burst at all.
It will expand. It would rise upwards even if it weren't brought into a warm room. As the temperature increases, the volume will also increase in order to maintain the pressure.
it becomes a mixture of a warm and cold water :)))
Nothing happens to the mass of the balloon. Mass is conserved, so the temperature of the balloon will not affect it's mass. Mass can be thought of the amount of "stuff" that makes up a balloon. It can be obtained by adding up the mass of all the molecules of rubber in the balloon. Obviously, putting the balloon in a warm room will not change the number of molecules in the balloon, therefore the mass stays constant. The volume of the balloon will probably increase. Because volume increases but mass remains constant, the density of the balloon would decrease. D = m/v
If you wait long enough, you eventually wind up with one warm balloon and one cold one.