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Answer:
40 °F is approximately 4.44°C
The equation is C = (F - 32) × 5/9
In this case, the answer is about 4.444 degrees Celsius.
---
The rule for getting this, is as follows:
Subtract 32 from 40, and see that 40 is 8 Fahrenheit degrees above the freezing point of water, under standard conditions. The freezing point is also known as 0 C.
Now, each time the temperature rises 9 degrees F, it also rises 5 degrees C. The boiling point of water is 212 F (or 180 degrees above 32), and it is 100 degrees C.
So, take 5/9 times 8, to get the centegrade equivalent of 40 °F.
This calculation gives 4 4/9, or 4.44444, approx.;
which is the answer we were seeking.
4.4 °C
The equation is C = (F - 32) × 5/9
In this case, the answer is about 4.444 degrees Celsius.
---
The rule for getting this, is as follows:
Subtract 32 from 40, and see that 40 is 8 Fahrenheit degrees above the freezing point of water, under standard conditions. The freezing point is also known as 0 C.
Now, each time the temperature rises 9 degrees F, it also rises 5 degrees C. The boiling point of water is 212 F (or 180 degrees above 32), and it is 100 degrees C.
So, take 5/9 times 8, to get the centegrade equivalent of 40 °F.
This calculation gives 4 4/9, or 4.44444, approx.;
which is the answer we were seeking.
4.4 °C
Contributor:
Viper1usmc
Viper1usmc
First answer by Viper1usmc.
Last edit by Moobot.
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