For this you need the atomic (molecular) mass of C2H5OH. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. C2H5OH= 46.1 grams1.271 grams C2H5OH / (46.1 grams) = .0276 moles C2H5OH
NaH2PO4(aq) + H2OàH3PO4(aq) + NaOH(aq) H3PO4(aq)ßàH+(aq) + H2PO4_(aq) H2PO4-(aq)ßàH+(aq) + HPO42-(aq) HPO42-(aq)ßàH+(aq) + PO43-(aq)
SO42-(aq) + Ca2+(aq) ---> CaSO4(s)
NH3 (aq)+ HBr(aq) --> NH4+ (aq)+ Br- (aq)
Zn (s) + 2HCI (aq) -- H2 (g) + ZnCI2 (s) Apex
NaCl(s) + C2H5OH(l) --> NaOH(aq) + C2H5Cl(aq)
C2H5OH (s) + 3O2 (g)+ Heat --> 2CO2 (aq)+ 3H2O (l)
C2H5OH is named asethyl alcohol
C2H5OH(liquid) ® C2H5OH(gas)
c2h5oh+h2o
79c
80c
88c
80c
35 c
80 degrees Celsius
C2h5oh+3o2---------->2co2+3h2o