i am almost positive it is 22.4 Liters per mole. The conversion for molecules to mole is 6.023 x 10^23 (avogadros number) and the relationship from grams to moles is dependant upon the molecular weight of the molecule you are talking about.
1 mole of any gas at STP (273.15 K and 1 atm) = 22.414 litres or 22,414 cm3
If you are using a different standard temperature and/or pressure, the molar volume of an ideal gas is V/n = RT/P
Where:
V/n = molar volume
R = ideal gas constant
T = absolute temperature
P = absolute pressure
I am going to assume that you mean 66.3L.
1 mole gas = 22.4L
66.3L gas x 1mol/22.4L = 2.96 moles gas
At S.T.P, no of moles X 22.414 = volume of a gas.
22.4 Liters
22.4L
At STP, 1 mol or 6.02x10^23 representative particles, of any gas occupies a volume of 22.4 Liters. (chemistry)
A mole of ideal gas at STP takes up 22.4 L.
We know that one mole of any gas at STP occupies 22.4 liters of volume. We also know that one mole of carbon dioxide is 44.01 grams of CO2. If there are 44.01 grams of this gas in 22.4 liters at STP, then there will be about 0.98 grams of CO2 in half a liter (500 ml) of the gas at STP.
Acetylene is C2H2, with a molar mass of 26g/mol. 49.6g of it = 1.9 moles. At STP, 1 mole of any gas occupies a volume of 22.4 liters, so 1.9 moles at STP would have a volume of 42.56 liters.
Molar volume = 22.4141 L/moleat standard temperature (melting ice) T = 273.15 K and standard pressure po= 1 ATM (= 1.01325*105 Pa)(At room temperature T=298 K and p=po the molar volume is 24.5 L/mole)
22.4L
1 mole of gas at STP occupies 22.4 liters.
22.4 L. At STP 1 mole of any gas will always be equal to 22.4 L.
At STP, 1 mol or 6.02x10^23 representative particles, of any gas occupies a volume of 22.4 Liters. (chemistry)
A mole of ideal gas at STP takes up 22.4 L.
Most commonly, this refers to the volume of a gas at Standard conditions of Temperature and Pressure (often abbreviated, STP). This standard allows accurate comparisons of volumes. The volume of a gas (any gas) at STP is 22.4 liters per mole.
We know that one mole of any gas at STP occupies 22.4 liters of volume. We also know that one mole of carbon dioxide is 44.01 grams of CO2. If there are 44.01 grams of this gas in 22.4 liters at STP, then there will be about 0.98 grams of CO2 in half a liter (500 ml) of the gas at STP.
Acetylene is C2H2, with a molar mass of 26g/mol. 49.6g of it = 1.9 moles. At STP, 1 mole of any gas occupies a volume of 22.4 liters, so 1.9 moles at STP would have a volume of 42.56 liters.
Molar volume = 22.4141 L/moleat standard temperature (melting ice) T = 273.15 K and standard pressure po= 1 ATM (= 1.01325*105 Pa)(At room temperature T=298 K and p=po the molar volume is 24.5 L/mole)
There are always ONE mole of gas in 22,4 L gas of any kind (even gaseous mixtures like air) at stp.So 68.5 (L) / 22.4 (L/mole) = 3.06 mole gas in 68.5 L (at STP)
Molar gas volume is the volume of ONE moel of gas. It only depends on the pressure and temperature, not on the kind of gas. Molar volume at standard temperature and standard pressure is always 22,4 Litres (for any gas)
The molar volume doesn't depend on the identity of the gas. One mole of any ideal gas at STP will occupy 22.4 liters.