The "full load current" is the current taken by a motor when it is delivering its full rated output power. Now, how is the "full load current" different to the "starting current"- is the "full load current" higher or lower than the starting current? And what about the lengths of time that a motor can safely run on "starting" and "full load" currents? And how do these currents affect the temperature of the motor casing, its windings and its surroundings?
The full load current of a 2.2KW single phase motors is 37 at 110V ac and 19 and 17 at 220V ac and 240V ac respectively. FLC varies with the type of motors and may be determined by the motor rating plate in each case.
You don't specify voltage, power factor, or efficiency, so I will make some assumptions. How about 480V three phase running delta, power factor 0.92, efficiency 0.96...
Divide 100 KW by 0.92 PF to get 109 KVA. Divide again by 0.96 EF to get 113 KVA. Divide by 0.480 KV to get 236 amperes. Divide by 3 to get 79 amperes per winding. Multiply by 1.732 (square root of 3) to get 136 amperes per phase.
That's an awful lot of amperes, forcing rather large windings. I would consider a higher voltage, perhaps 4.160 KV, which would bring the current down to 16 amperes per phase, but now you need better insulation. In either case, you need some serious engineering for this one.
full load current of 1 hp motor is approx. 7A
To answer this question the motor voltage is needed.
Cannot be answered without knowing the working voltage.
Full load amps is the maximum rated amps that the motor should draw according to its nameplate rating. Running load amps is the actual amperage the motor is drawing at that point in time when the test is taken. Some motor loads vary depending on if the load is cyclic. The reading on this type of motor would be from no load amps to full load amps.
no load voltage means there is no connected devices operating on the circuit. usually the voltage reading will reflect the normal or highest voltage reading in the circuit. full load voltage is measured when all devices in the circuit are operating at the same time. initial load startup will usually drop the voltage somewhat, but it should recover in a short period of time
In a simple circuit, the amount of voltage, and the resistance of the load. Amps = volts / ohms. For a motor, the back EMF when the rotor is turning reduces the effective voltage across the windings, reducing the current. That is why a motor may burn out if it is powered but cannot turn.
To understand various considerations for proper co-ordination, time-current characteristics of thermal overload relay (curve B), H.R.C. fus (curve C), MCCB with only instantaneous release (curve D) and MPCB (curve E) are superimposed on motor starting characteristics (curve A) in Fig. 3. Intersection of characteristics of thermal overload relay and Fuse / MCCB is termed as 'cross-over point' and corresponding current as 'cross-over current' lco. Following points are to be ensured while selecting components to have properly co-ordinated motor protection: lContactor rating (AC-3) should be more than or equal to motor full load current (if application is AC-3 duty) Thermal overload relay of appropriate 'Trip Class' is selected. Time current characteristics of the relay should remain above motor starting characteristics as shown in Fig. 3. For fault currents lower than 'cross-over current lco', relay will respond faster than SCPD and hence contactor will interrupt the fault current. Fault currents higher than lco will be interrupted by SCPD. Hence, rating of contactor is so chosen that lco is less than rated breaking capacity of the contactor Relay and contactor should be able to withstand lco for a duration equal to trip time of the relay. IEC / BS / EN standards require that the contactor should be able to withstand at least current equal to 8 times AC-3 rating (6 times for ratings higher than 630A) for 10 seconds While using MCCB or MPCB, attention needs to be given to motor peak starting current. To avoid operation of MCCB / MPCB during starting, instantaneous release is chosen as 12 times the full load current of the motor. This thumb rule assumes motor starting current equal to 6 times full load current In case of high efficiency motors, starting currents could be about 8 times full load current. For such application, MCCB rating need to be selected such that instantaneous release setting is higher than 12 (about 14) times full load current to avoid nuisance tripping during starting. Similarly, while using MCCB as a SCPD for Star-Delta starter, consideration needs to be given to peak current associated with change over from Star to delta. Instantaneous release of MPCB is normally set at 12 times the rating. Hence, possibility of nuisance tripping needs to be considered while using MPCB for protection of high efficiency motors or for star delta starter.
it means a current as in an electrical current
Full load starting current is typically in the region of 5or 6 times the full load motor current;.
22 kw motor how much takes ampares with load
not you kan not start 22kw motor with 25kva generator (οχι)
As the no load current is the current due to core losses of the motor which is very small .in no load terminals are open circuited no current flows through it, a small current flows which is due to core
3phese 460 volt 75 kw a/c drivi full load current
The ratio is between 30% to 40 %
FLA: Full Load Ampere. Its the current drawn by the motor when the motor is running at full load FLA = kW / (1.732*V*pf*efficiency*100)
Across the line starting of a motor can be as high as 300% of the full load amps.
According to 2011 nfpa 70 nec Motor conductors are sized with the flc- full load current or the nameplate rating fla- full load amperes
Because full speed is unloaded. As you load the motor, speed decreases, and slip increases, with an accompanying increase in current.
While starting a motor from standstill to its rated speed, the motor has to overcome the inertia and generate enough torque to over come it. In the process the motor takes higher current during the starting. Once started and set in motion the current reduces ti its normal value. Full load current is lower than the starting current normally.
decrease in starting and running torque and speed is almost constant from no load to full load. it's because the field voltage is consant and current is varied.