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What does Y1 mean in terms of classification into the Military?
Wiki User
∙ 12y ago
During the Vietnam War there were the following classifications: Class 1, 2, 3, and 4. 1-A, 1-A-O, 1-C, 1-D, 1-H, 1-O, and 1-W. 2-A, 2-C, 2-D, and 2-S. 3-A. 4-A, 4-B, 4-C, 4-D, 4-F, 4-G, and 4-W. 1-A meant the man was available for military service. 1-W meant he was a Conscientious Objector. 4-F meant the man was unfit for military service.
Tyree Cassin
Wiki User
∙ 14y agoDuring the Vietnam War there were the following classifications: Class 1, 2, 3, and 4. 1-A, 1-A-O, 1-C, 1-D, 1-H, 1-O, and 1-W. 2-A, 2-C, 2-D, and 2-S. 3-A. 4-A, 4-B, 4-C, 4-D, 4-F, 4-G, and 4-W. 1-A meant the man was available for military service. 1-W meant he was a Conscientious Objector. 4-F meant the man was unfit for military service.
Anonymous
Wiki User
∙ 12y agoy means you and 1 means you get that person
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How do you transfer point slope form into slope intercept form?
First substitute the coordinates of (x1, y1) into the equation, then simplify the equation so it has y in terms of x. y - y1 = m(x - x1) y - y1 = mx - mx1 y = mx - mx1 + y1 y = mx + (y1 - mx1) y = mx + (C)
When using the slope formula does it have to be (y2-y1)(x2-x1) or can it be (y1-y2)(x1-x2)?
If you mean: (y2-y1)/(x2-x1) and (y1-y2)/(x1-x2) then either works out the same.
How do you find the mean of ordered pair?
Each element is the mean of the corresponding elements. Thus, the mean of (x1, y1) and ( x2, y2) is [( x1 + x2)/2, (y1 + y2)/2]
What formula with functions can you enter to calculate the range of values in Y1 to Y10?
There are many calculations that could be done: =SUM(Y1:Y10) =AVERAGE(Y1:Y10) =MAX(Y1:Y10) =MIN(Y1:Y10) =COUNT(Y1:Y10)
What is 3x-y1?
If you mean: 3x-y = 1 then it is a straight line equation
What is 5x-y1?
5x-y1 = 4
How do you find the slope of a given?
for a linear function m= rise/ run if given 2 points on the graph m= (y2-y1)/(x2-x1) remember to simplify (lowest terms)! the 2 behind the x and the y is are not exponents! They mean the range in the second bracket: ex. (5,6)<--- 6= x2 5= x1 (7,8) <--- 8= y2 7=y1
What is a slope used for?
It shows the relationship of y in terms of x. [y = (yIntercept) + ((slope)*(x))] [slope = (y2 - y1)/(x2 - x1)]
What is the midpoint in math terms?
GIven 2 distance points (x1,y1) and (x2,y2) we can draw a line between those point and the midpoint formula finds the midpoint of that line. Call the midpoint (m1,m2) then it is [ (x1+x1 )/2 , (y1+y2/2)]
C program to design a car?
#include<stdio.h> #include<graphics.h> #include<math.h> #include<conio.h> #include<dos.h> #include<alloc.h> #include<stdlib.h> #define RAD 3.141592/180 class fig { private: int x1,x2,y1,y2,xinc,yinc; public: void car() { xinc=10;yinc=10; x1=y1=10; x2=x1+90;y2=y1+35; int poly[]={x1+5,y1+10,x1+15,y1+10,x1+20,y1,x1+50,y1,x1+60,y1+10,x1+90,y1+17,x1+90,y1+20,x1+5,y1+20,x1+5,y1+10}; setfillstyle(SOLID_FILL,LIGHTGRAY); setlinestyle(SOLID_LINE,1,2); setcolor(4); drawpoly(9,poly); line(x1+15,y1+10,x1+60,y1+10); line(x1+20,y1+10,x1+20,y1); line(x1+35,y1+10,x1+35,y1); line(x1+50,y1+10,x1+50,y1); floodfill(x1+18,y1+8,4); floodfill(x1+28,y1+8,4); floodfill(x1+36,y1+8,4); floodfill(x1+52,y1+8,4); setfillstyle(SOLID_FILL,4); floodfill(x1+18,y1+12,4); setfillstyle(SOLID_FILL,BLUE); bar(x1+5,y1+20,x1+90,y1+25); setcolor(DARKGRAY); circle(x1+20,y1+25,8); circle(x1+20,y1+25,6); setfillstyle(1,8); floodfill(x1+21,y1+25,8); circle(x1+70,y1+25,8); circle(x1+70,y1+25,6); floodfill(x1+71,y1+25,8); int size=imagesize(x1,y1,x2,y2); void far *buf=farmalloc(size); getimage(x1,y1,x2,y2,buf); while(!kbhit()) { putimage(x1,y1,buf,XOR_PUT); x1+=xinc;x2+=xinc; if(x2<(getmaxx()-10)) putimage(x1,y1,buf,COPY_PUT); else { cleardevice(); x1=10;x2=x1+90; y1+=yinc;y2+=yinc; if(y2<(getmaxy()-10)) { putimage(x1,y1,buf,COPY_PUT); } else {y1=10;y2=y1+35;} } delay(200); } farfree(buf); getch(); } } } } void main() { int gd=DETECT,gm; initgraph(&gd,&gm,"d:\\cplus"); fig f; f.car(); cleardevice(); closegraph(); }
How do you draw a square using line command?
Line (x1, y1, x2, y1); Line (x2, y1, x2, y2); Line (x2, y2, x1, y2); Line (x1, y2, x1, y1);
What is the answer to 3x y1 x y1?
{3x +y =1 {x+y= -3
