What is algorithm to sum two natural numbers using c?

Not necessarily.1/3 + 1/3 = 2/3 which is (must be) rational, but is not a natural number.

Yes. You know this is true because you learned a process-- an "algorithm"--for adding two numbers together, and if you start with two whole numbers, the result is also a whole number.

include<iostream.h> void main() { int a,b,sum; cout<<"Enter the two nubers"; cin>>a>>b; sum=a+b; cout<<"The sum is "<<sum; return 0; }

Algorithm in C Language:int *a,*b; //Declaraction of the two pointersint sum;scanf("%d%d",a,b); //Reading values of the 2 variablessum=*a+*b;printf("SUM = %d",sum);

No. The difference can be a negative integer which is not a natural number.