Due to the calculations you make using your genetic code dictionaries, you must go backwards using the third letter of codon and then second and then first. Then, you have your answer for what the amino acid sequence would be for cga gaa guc. Then you just flip cga and guc, keeping gaa in the middle.
To get the amino acid sequence you separate the letters into chunks of three (codons). Ex. AUG is Met (methionine).
So the full sequence left to right (5' to 3'):
A UGC CAG AGC AAU AUU AAG UGA
Cys Gln Ser Asn Ile Lys X
Cysteine-Glutamine-Serine-Asparagine-Isoleucine-Lysine-stop codon
You have a sequence that is not a multiple of three (3 per codon) so either that is a mistake or there is a frameshift mutation
First you have to divide the sequence into 3s utg tug uuc cgc tgc tgu then go to this website and for each set of three follow the letters in the chart. This will lead you to the word it codes for. Combine them together for the "sentence".
To translate the DNA, you first must transcribe it to an mRNA sequence. This means finding the matching set of base pairs that would belong on an mRNA molecule (U instead of T). Translating from left to right yields the sequence AUGCUUGAACCCAGG. Split the mRNA sequence into groups of three bases, each of which will code for an amino acid: AUG|CUU|GAA|CCC|AGG. Translators for these can be found almost anywhere; however, almost every sequence will begin with the amino acid methionine, as its codon also doubles as the start codon.
Translating the sequence results in the amino acid sequence Methionine-Leucine-Glutamate-Proline-Arginine, abbreviated Met-Leu-Glu-Pro-Arg or MLEPR.
The mRNA sequence would be:
GAC CCG AAU UUC GCG
The amino acid sequence from this would be:
Aspartic acid (D), Proline (P), Asparagine (N), Phenylalanine (F), Alanine (A)
UAAGCUGGUGC
taagctggatc
Only one mRNA codon codes for Methionine - AUG.
AGUCUUGGGCUUUGCCCC If the Adenine nucleotides were deleted then both the A and U nucleotides would be affected. Only the G and C would be allowed to code for the protein. GCGGGCGCCCC would be the resulting sequence. A codon is made of three nucleotides. So: GCG GGC GCC CC G CGG GCG CCC C GC GGG CGC CCC would be the only sequences that could result. This would be only three amino acids.
TGCA
Species Nucleotide sequence of gene ABX A TAC ATA CGC GGG ACC TTT AGT GGG GCC CCC ACT B TAC ATA CCC CCG ACC TAT CGC GGG GCG CCC ACT C TAC ATA CCC CCG ACC TTT CGC GGG GCG CCC ACT D TAC ATA CGG GGG AAA TTT CGC TTT GCG CGC ACT Species B and Species C
The information code into the DNA is used to code all the processes happening in a living beings and needed to sustain its life. Proteins production is a particularly important class of such processes, due to the importance of proteins in the biological mechanism. Since a protein is essentially a sequence of 20 base amino acids, the codes driving proteins synthesis inside the cell is a transcription of the amino acid sequence characterizing the protein. When the protein is produced in the controlled chemical environment inside the cell, the amino acids chain will configure in the correct stereographic structure driven by the need of minimizing the molecule free energy so to constitute a functional biomolecule.In eukaryote (the cells of more evolved beings), proteins are synthesized into the ribosomes, the specialized cell organelles. Even if the process is quite complex, in a first approximation it can be described as follows. The sequence of amino acids encoded in a DNA gene is translated into a mRNA that is used by the ribosome to assembly the correct sequence of amino acids while they are conveyed to the synthesis site by tRNA.Each amino-acid is coded by a set of three nucleobases, called codon, thus the mRNA is read codon by codon during the protein synthesis. Specific codons, called START and STOP , are used begin and to stop the synthesis. Since four nucleobases are available, there are 64 possible codons, so that each amino acid and the START and STOP signals are coded by more than one codon. The coding Table used in protein synthesis is reported in the following TableAmino acidCodonsAlaGCT, GCC, GCA, GCGArgCGT, CGC, CGA, CGG, AGA, AGGAsnAAT, AACAspGAT, GACCysTGT, TGCGlnCAA, CAGGluGAA, GAGGlyGGT, GGC, GGA, GGGHisCAT, CACIleATT, ATC, ATALeuTTA, TTG, CTT, CTC, CTA, CTGLysAAA, AAGMetATGPheTTT, TTCProCCT, CCC, CCA, CCGSerTCT, TCC, TCA, TCG, AGT, AGCThrACT, ACC, ACA, ACGTrpTGGTyrTAT, TACValGTT, GTC, GTA, GTGSTARTATGSTOPTAA, TGA, TAG
AGG, AGA, CGA, CGC, CGU, and CGG specify arginine.
Only one mRNA codon codes for Methionine - AUG.
G-A-T-T-A-G-C-C-T-A-A-G-G-T-C-GDNA base-pairing rulesAdenine - ThymineCytosine - GuanineRNA base-pairing rulesAdenine - UracilCytosine - Guanine
is cgc ugc approved
cgc is better
The population of CGC Japan is 334.
cgc landran
aug aaa aag aac uau uuc cgc gag ggc uau ggg ggc aac aag uua
CGC Japan was created on 1973-10-27.
he old dogma of molecular biology held that for every gene there was one protein (and therefore one mRNA). This is not the case, as we now know. There are many different mRNAs that can arise from a single gene, depending on splicing, promoting and enhancing regions etc. The answer to the first question is 'it depends'-on the gene, the cell conditions etc. Introns were thought of as junk DNA, but they now appear to play at least a minor regulatory role in many cases, as well as influencing splicing etc. Amino acids can be coded for by a number of different codons (sets of 3 nucleotides, the unit with which the DNA sequence is read and interpreted) due to the DNA sequence redundancy. This means that many of the amino acids found in a chain may have been coded by any of (up to 6) different codon sequences, so you can't tell exactly the DNA sequence just from the amino acid sequence. (e.g. Argenine is coded by CGI, CGC, CGA and CGG, which means you can't tell which sequence on the DNA coded for the argenine, it could be any of the four possible choices)
AGUCUUGGGCUUUGCCCC If the Adenine nucleotides were deleted then both the A and U nucleotides would be affected. Only the G and C would be allowed to code for the protein. GCGGGCGCCCC would be the resulting sequence. A codon is made of three nucleotides. So: GCG GGC GCC CC G CGG GCG CCC C GC GGG CGC CCC would be the only sequences that could result. This would be only three amino acids.
TGCA