Sulfuric acid H2SO4 will give away 2 protons H+ for this reason its normality is 2 times its molarity.
so for H2SO4 M = 2N
For HCl M= 1N because HCl has only one proton H+
H3PO4 for example has 3N = M
so for your case, 6M = 2N and N= 6/2 = 3.
1 Normal (N) is made by adding 28 ml of concentrated sulfuric acid with deionized water to a final volume of 1 Liter (L).
Concentrated Sulfuric acid is 35.71 N, where 2 N = 1 M (molarity).
It is 1N, as each H2SO4 unit exchanges 2 Hs
Normality - molarity/functionality so 1.25/2 = 0.625N
The molecular mass of H2SO4 is twice of its equivalent mass so normality of 2M solution must be 4N
2.7 N
0.08 n
1 M solution of H2SO4 is concentrated than 1 N because Molarity is no. of moles dissolved per Litre of the solution here i.e 98 g of H2SO4 dissolved per litre. Normality is Gram equvalent weight (no. of electron lost or gained in chemical reaction or acidty or basisty) dissolved per litre. equvalent weight of H2SO4 is 98/2= 49 mean 1 N of H2SO4 is 49g dissolved per litre.
- log(0.000626 M H2SO4) = 3.2 pH -----------
30 mL water.
You need 49,8 mL H2SO4 6,4M.
0.08 n
The normality of a solution is the gram equivalent weight of a solute per liter of solution. For example, 1 M sulfuric acid (H2SO4) is 2 N for acid-base reactions because each mole of sulfuric acid provides 2 moles H+ ions.
1 M solution of H2SO4 is concentrated than 1 N because Molarity is no. of moles dissolved per Litre of the solution here i.e 98 g of H2SO4 dissolved per litre. Normality is Gram equvalent weight (no. of electron lost or gained in chemical reaction or acidty or basisty) dissolved per litre. equvalent weight of H2SO4 is 98/2= 49 mean 1 N of H2SO4 is 49g dissolved per litre.
The normality is o,3.
- log(0.000626 M H2SO4) = 3.2 pH -----------
30 mL water.
You need 49,8 mL H2SO4 6,4M.
The first solution is more concentrated because it contains 6 moles of H2SO4 per one liter of solution. The second solution is less concentrated because it contains 0.1 moles of H2SO4 in one liter. In equal amounts of each example, the first would have more H2SO4.
I read this as a 1 molar solution, which is to say, a concentration of one mole of NaOH per liter of solution. If that is not what you mean, please don't abbreviate the words (whatever the M and the m stand for) and write them out in full. I don't know what else it would mean other than molar.
MW of H2SO4 is 98.08. 2M = 2 x 98.08 in 1 L of water (1 gram=1 ml). Take 500 ml water in a 1 L measuring cylinder. Add 196.16 ml slowly along the side into water in the measuring cylinder. Use 50 ml pipette with automated pipettor. If needed you may want to keep the cylinder in ice to take care of the heat generated. Then make up to volume to 1 L with water. Eq. wt for H2SO4 = 98.08/2 = 49.039. SO for 2N solution, 2 eq.wt in 1 L. 98.08 ml in 1 L water adopting the method cited above.
Remember M1V1=M2V2. (M is for molarity. V is for volume.)So:0.25M x V1 = 0.50 M x 0.050 LV1 = 0.50 M x 0.050L / 0.25 M = 0.1 LWait! You need it in mL so 0.1 L x 1000 = 100 mL
Concentrated H2SO4 is 96 %.( In laboratory ) As density of concentrated H2SO4 is 1.84gm/ml we will need this number as well, and as the atomic mass of H2SO4 is 98.08,as it is dibasic for normality it is 49 hence, Calculation=((96/100)(1000)(1.84))/49=36.04 If H2SO4 concentrated is 36.04 M then for make a 1L solution of 1M H2SO4 (36.04)X (x) = 1X(1) x = 1 X(1) / (36.04) x=0.0277gm/ml of water x = 27.7 mL of 36M H2SO4 per liter Hence for 1N H2SO4 dissolve 27.7ml of it to 1000ml of solvent(Water) that means for 0.1 N H2SO4 2.77 ml of it to 1000mL of solvent.